\(12\frac{3}{7}\%+12\frac{5}{7}\%\)
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2\(\frac{2}{12}\)+ X = \(\frac{5}{7}\)+ \(\frac{8}{12}\)
\(\frac{13}{6}\)+ X=\(\frac{29}{21}\)
X= \(\frac{29}{21}\)- \(\frac{13}{6}\)
X=\(\frac{-11}{14}\)
\(|2^2_{12}\)\(+x=\frac{5}{7}+\frac{8}{12}\)
\(2+x=\frac{5}{7}+\frac{1}{2}\)
\(2+x=\frac{17}{14}\)
\(x=\frac{17}{14}-2\)
\(x=\frac{-11}{14}\)
a, -5/12 + 1/-4 = -5/12 + -1/4 = -5/12 + -3/12 = -8/12 = -2/3
b, 5/12 + -3/28 = 35/84 + -9/84 = 26/84 = 13/42
c, -7/12 + 3/55 = -385/660 + 36/660 = -349/660
d, -5/7 + -3/4 = -20/28 + -21/28 = -41/28
\(\frac{3}{12}+\frac{2}{4}-\frac{2}{12}\)
\(=\frac{3}{12}+\frac{6}{12}-\frac{2}{12}\)
\(=\frac{3+6-2}{12}\)
\(=\frac{7}{12}\)
\(\frac{3}{12}+\frac{2}{4}-\frac{2}{12}\)
\(=\frac{3}{12}+\frac{6}{12}-\frac{2}{12}\)
\(=\frac{9}{12}-\frac{2}{12}\)
\(=\frac{7}{12}\)
\(12\frac{4}{5}\)=\(\frac{64}{5}\).
Ta có :
\(\frac{64}{5}+\frac{4}{5}=\frac{68}{5}\)
\(12\frac{4}{5}+\frac{4}{5}=\frac{64}{5}+\frac{4}{5}=\frac{68}{5}\)
\(\frac{12}{5}+\frac{23}{4}=\frac{48}{20}+\frac{115}{20}=\frac{163}{20}\)
\(2\frac{4}{3}+\frac{4}{12}=\frac{2.3+4}{3}+\frac{4}{12}=\frac{10}{3}+\frac{4}{12}=\frac{40}{12}+\frac{4}{12}=\frac{44}{12}=\frac{11}{3}\)
\(2\frac{4}{3}=\frac{10}{3}\)
\(\frac{10}{3}+\frac{4}{12}=\frac{120}{36}+\frac{12}{36}\)
\(=\frac{132}{36}=\frac{22}{6}=\frac{11}{3}\)
\(12\frac{3}{7}\%+12\frac{5}{7}\%=\frac{176}{7}\%\)