mọi ng giúp e
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`B.I.`
`1.` a
`2.` c
`3.` d
`4.` a
`5.` D
`6.` C
`7.` B
`8.` A
`II.`
`1.` Shrine
`2.` impressed
`3.` traditional
`4.` for
`C.I.`
`1.` T
`2.` T
`3.` F
`4.` F
`II.`
`1.` Yes, Jeans the most popular kind of clothes almost everywhere, rich people and poor people wear them too.
`2.` Jeans the only kind of tradtional clothes in the United States.
`3.` Because everybody wants to be modern, young and independent.
`4.` (Tự trả lời)
`D.I.`
`1.` Many letters can be written to my pen pal in english by me.
`2.` has done
`3.` I wish today were a holiday.
`4.` I missed the bus, so I came to the meeting late.
1, \(x^2\) - \(x\) + \(\dfrac{1}{4}\) = 0
\(x^2\) - 2.\(x\).\(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) = 0
(\(x\) - \(\dfrac{1}{2}\))2 = 0
\(x\) - \(\dfrac{1}{2}\) =0
\(x\) = \(\dfrac{1}{2}\)
2, \(x^2\) - 10\(x\) = -25
\(x^2\) - 10\(x\) + 25 = 0
(\(x\) - 5)2 = 0
\(x\) - 5 =0
\(x\) = 5
a) phép tính đã cho bằng 24x2y3z2 : (-6x2y2z2) +(-12x3y2z3) : (-6x2y2z2) + 36x2y2z2 : (-6x2y2z2) = -4y+2xz-6. Thế x,y,z vào rồi tính nha
câu b khi nãy mình giải ở dưới rồi :)
2.26:
a. $x^2-6x+9-y^2=(x^2-6x+9)-y^2=(x-3)^2-y^2$
$=(x-3-y)(x-3+y)$
b. $4x^2-y^2+4y-4=4x^2-(y^2-4y+4)$
$=(2x)^2-(y-2)^2=(2x-y+2)(2x+y-2)$
c. $xy+z^2+xz+yz=(xy+xz)+(z^2+yz)=x(y+z)+z(z+y)$
$=(y+z)(x+z)$
c.
$x^2-4xy+4y^2+xz-2yz$
$=(x^2-4xy+4y^2)+(xz-2yz)$
$=(x-2y)^2+z(x-2y)=(x-2y)(x-2y+z)$
2.27:
a. $x^3+y^3+x+y=(x^3+y^3)+(x+y)$
$=(x+y)(x^2-xy+y^2)+(x+y)=(x+y(x^2-xy+y^2+1)$
b. $x^3-y^3+x-y=(x^3-y^3)+(x-y)=(x-y)(x^2+xy+y^2)+(x-y)$
$=(x-y)(x^2+xy+y^2+1)$
c.
$(x-y)^3+(x+y)^3=(x^3-3x^2y+3xy^2-y^3)+(x^3+3x^2y+3xy^2+y^3)$
$=2x^3+6xy^2=2x(x^2+3y^2)$
d.
$x^3-3x^2y+3xy^2-y^3+y^2-x^2$
$=(x^3-3x^2y+3xy^2-y^3)-(x^2-y^2)$
$=(x-y)^3-(x-y)(x+y)=(x-y)[(x-y)^2-(x+y)]$
$=(x-y)(x^2-2xy+y^2-x-y)$