Tìm x
[x-35]-120=0
124+[118-x]=217
156-[x+61]=82
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a) (x-35)-120=0
x-35= 120
➩x = 155
b)310-(118-x)=217
118 -x = 93
➩ x = 25
c)156-(x+61)=82
➩ x + 61 = 74
➩ x = 13
a: Ta có: \(x-35-120=0\)
\(\Leftrightarrow x-155=0\)
hay x=155
b: Ta có: \(310-\left(118-x\right)=217\)
\(\Leftrightarrow118-x=93\)
hay x=25
c: Ta có: \(156-\left(x+61\right)=82\)
\(\Leftrightarrow x+61=74\)
hay x=13
a/ \(\left(x-35\right)-120=0\)
\(\Leftrightarrow x-35=0+120\)
\(\Leftrightarrow x-35=120\)
\(\Leftrightarrow x=120+35\)
\(\Leftrightarrow x=155\)
Vậy ...
b/ \(124+\left(188-x\right)=217\)
\(\Leftrightarrow188-x=217-124\)
\(\Leftrightarrow188-x=93\)
\(\Leftrightarrow x=95\)
Vậy ...
b/ \(156-\left(x+61\right)=82\)
\(\Leftrightarrow x+61=74\)
\(\Leftrightarrow x=13\)
Vậy ..
a)(x-35)-120=0 b)124+(118-x)=217 c)156-(x+61)=82
x-35 = 0+120=120 118-x =217-124=93 x+61 = 156-82=74
x = 120+35=155 x = 118-93=25 x =74-61=13
suy ra x=155 suy ra x= 25 suy ra x=13
a) ( x - 35 ) - 120 = 0
<=> x - 35 = 120
<=> x = 155
b) 124 + ( 118 - x ) = 217
<=> 118 - x = 93
<=> x = 25
c) 156 - ( x + 61 ) = 82
<=> x + 61 = 74
<=> x = 13
(x-35)-120=0
x-35 = 0 + 120
x-35 = 120
x = 120 + 35
x = 155
124+(118-x)=217
118-x = 217-124
118-x = 93
x = 118 - 93
x = 25
156-(x+61)=82
x + 61=156-82
x+61 = 74
x = 74 - 61
x = 13
(x-35)-120=0
x-35 = 0+120
x-35 = 120
x = 120-35
x = 85
124 + (118-x)=217
118-x=217-124
118-x=93
x=118-93
x=25
156-(x+61)=82
x+161=156-82
x+161=74
x=161-74
x=87
do la bai cua minh,co cho sai nao thi sua cho minh nhe
a, (x - 35) - 120 = 0
=> x - 35 = 120
=> x = 155
b, 124 + (118 - x) = 217
=> 118 - x = 93
=> x = 25
c, 156 - (x + 61) = 82
=> x + 61 = 74
=> x = 13
a)
(x-35)-120=0
=>x-35=0+120
=>x-35=120
=>x=120-35
=>x=85
b)
124+(118-x)=217
=>118-x=217-124
=>118-x=93
=>x=118-93
=>x=25
c) 125-(x+61)=82
=>x+61=125-82
=>x+61=43
=>x= 43-61
=>x= -18
a)
(x-35)-120=0
=>x-35=0+120
=>x-35=120
=>x=120-35
=>x=85
b)
124+(118-x)=217
=>118-x=217-124
=>118-x=93
=>x=118-93
=>x=25
c) 125-(x+61)=82
=>x+61=125-82
=>x+61=43
=>x= 43-61
=>x= -18
a) (x - 35) - 120 = 0
x - 35 = 120
x = 155
b) 124 + (118 - x) = 217
118 - x = 93
x = 25
c) 156 - (x + 61) = 82
x + 61 = 74
x = 13
a, ( x - 35 ) - 120 = 0
( x - 35 ) = 0 + 120
x - 35 = 120
x = 120 + 35
x = 155
Vậy x = 155
b, 124 + ( 118 - x ) = 217
( 118 - x ) = 217 - 124
118 - x = 93
x = 118 - 93
x = 25
Vậy x = 25
c, 156 - ( x + 61 ) = 82
( x + 61 ) = 156 - 82
x + 61 = 74
x = 74 - 61
x = 13
Vậy x = 13
a) \(\left(x-35\right)-120=0\)
\(\Rightarrow x-35=0+120\)
\(\Rightarrow x=120+35\)
\(\Rightarrow x=155\)
b) \(124+\left(118-x\right)=217\)
\(\Rightarrow118-x=217-124\)
\(\Rightarrow x=118-93\)
\(\Rightarrow x=25\)
c) \(156-\left(x+61\right)=82\)
\(\Rightarrow x+61=156-82\)
\(\Rightarrow x=74-61\)
\(\Rightarrow x=13\)
a) ( x - 35 ) - 120 = 0
<=> x - 35 = 120
<=> x = 155
b) 124 + ( 118 - x ) = 217
<=> 118 - x = 93
<=> x = 25
c) 156 - ( x + 61 ) = 82
<=> x + 61 = 74
<=> x = 13