Tìm x biết
53 . 31 . x = 4929
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\(52\cdot31\cdot x=4929\\ \Leftrightarrow1612x=4929\\ \Leftrightarrow x=\dfrac{159}{52}\)
\(x\cdot1999=1999\cdot199,8\\ \Leftrightarrow x=199,8\)
a) 49 x ( X – 21 ) = 441 e) X : (12 + 13) = 7
X – 21 = 441:49 X : 25 = 7
X – 21 = 9 X = 7 x 25
X = 21 + 9 X = 175
X = 30
b) 53 x 31 x X = 4929 g) 429 : ( X + 31) = 11
31 x X = 4929 : 53 X + 31 = 429 : 11
31 x X = 93 X + 31 = 39
X = 93 : 31 ’ X = 39 – 31
X = 3 X = 8
c) 61 x (126 : X ) = 1281 h) 1 615 : (X x 19) = 17
126 : X = 1281 : 61 X x 19 = 1 615 : 17
126 : X = 21 X x 19 = 95
X = 126 : 21 X = 95 : 19
X = 6 X = 5
d) 79 x ( X : 23 ) = 316 i) 420 : ( X : 39 ) = 105
X : 23 = 316 : 79 X : 39 = 420 : 105
X : 23 = 4 X : 39 = 4
X = 4 x 23 X = 4 x 39
X = 92 X = 156
A : Hế lô,goắt ì do nêm ?
B : What ?
A : Goắt là cái gì ? diu min do nêm ì goắt
B : What are you saying ?
A : Do nêm ì goắt a diu xây inh
B : Wtf
105-(27-x) = 98
27-x = 105-98
27-x = 7
x = 27-7
x = 20
Vậy ...
53.31.x = 4929
1643.x = 4929
x = 4929:1643
x = 3
Vậy ...
Nhớ line cho mình nhé!
105 - ( 27 - x ) = 98 53 x 31 x x = 4929
( 27 - x ) = 105 - 98 ( 53 x 31 ) x x = 4929
( 27 - x ) = 7 1643 x x = 4929
x = 27 - 7 x = 4929 : 1643
x = 20 x = 3
Câu 1:
\(=\dfrac{21}{31}+\dfrac{1}{3}-\dfrac{44}{53}+\dfrac{10}{31}-\dfrac{9}{53}=\dfrac{1}{3}\)
Câu 2:
1: =>1,3x=-1,31
=>130x=-131
=>x=-131/130
2: =>(4,5-2x)=11/14:(-11/7)=-7/14=-1/2=-0,5
=>2x=5
=>x=5/2
a) \(\dfrac{25}{37}\times\dfrac{18}{29}+\dfrac{18}{29}\times\dfrac{12}{37}\)
\(=\dfrac{18}{29}\times\left(\dfrac{25}{37}+\dfrac{12}{37}\right)\)
\(=\dfrac{18}{29}\times\dfrac{37}{37}\)
\(=\dfrac{18}{29}\times1\)
\(=\dfrac{18}{29}\)
b) \(\dfrac{31}{85}\times\dfrac{11}{19}+\dfrac{31}{85}\times\dfrac{12}{19}-\dfrac{42}{19}\times\dfrac{31}{85}\)
\(=\dfrac{31}{85}\times\left(\dfrac{11}{19}+\dfrac{12}{19}-\dfrac{42}{19}\right)\)
\(=\dfrac{31}{85}\times\dfrac{-19}{19}\)
\(=\dfrac{31}{85}\times-1\)
\(=-\dfrac{31}{85}\)
c) \(\dfrac{16}{53}:\dfrac{17}{9}-\dfrac{16}{53}:\dfrac{17}{8}\)
\(=\dfrac{16}{53}:\left(\dfrac{9}{17}-\dfrac{8}{17}\right)\)
\(=\dfrac{16}{53}:\dfrac{1}{17}\)
\(=\dfrac{16}{901}\)
c) \(\dfrac{1}{5}\times\dfrac{12}{31}\times\dfrac{4}{3}+\dfrac{19}{31}\times\dfrac{4}{15}\)
\(=\dfrac{4}{15}\times\dfrac{12}{31}+\dfrac{19}{31}\times\dfrac{4}{15}\)
\(=\dfrac{4}{15}\times\left(\dfrac{12}{31}+\dfrac{19}{31}\right)\)
\(=\dfrac{4}{15}\times\dfrac{31}{31}\)
\(=\dfrac{4}{15}\times1\)
\(=\dfrac{4}{15}\)
a: =18/29*(25/37+12/37)
=18/29
b: =31/85(11/19+12/19-42/19)
=-31/85
c; =16/53(9/17+8/17)=16/53
d: =4/15(12/31+19/31)=4/15
\(\frac{31}{53}.\frac{17}{28}+\frac{31}{28}.\frac{11}{53}\)
\(=\frac{31}{53}.\frac{17}{28}+\frac{11}{28}.\frac{31}{53}\)
\(=\frac{31}{53}.\left(\frac{17}{28}+\frac{11}{28}\right)\)
\(=\frac{31}{53}.1\)
\(=\frac{31}{53}\)
\(\frac{31}{53}\times\frac{17}{28}+\frac{31}{28}\times\frac{11}{53}\)
\(=\frac{31}{53}\times\frac{17}{28}+\frac{31}{53}\times\frac{11}{28}\)
\(=\frac{31}{53}\times\left(\frac{17}{28}+\frac{11}{28}\right)\)
\(=\frac{31}{53}\times1\)
\(=\frac{31}{53}\)
53 . 31 . x = 4929
31 . x = 4929 : 51
31 . x = 93
x = 93 : 31
x = 3
Vậy x = 3