giải hộ ạ
(-12.2/7+8/9:3 1/2-2/7.5/18).3 1/2
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(-12.\(\dfrac{2}{7}\) + \(\dfrac{8}{9}\): 3\(\dfrac{1}{2}\) - \(\dfrac{2}{7}\).\(\dfrac{5}{18}\)). 3\(\dfrac{1}{2}\)
(-\(\dfrac{24}{7}\) + \(\dfrac{8}{9}\):\(\dfrac{7}{2}\) - \(\dfrac{5}{63}\)). \(\dfrac{7}{2}\)
= (-\(\dfrac{24}{7}\) + \(\dfrac{16}{63}\) - \(\dfrac{5}{63}\)).\(\dfrac{7}{2}\)
= (\(-\dfrac{216}{63}\) + \(\dfrac{16}{63}\) - \(\dfrac{5}{63}\)). \(\dfrac{7}{2}\)
= - \(\dfrac{205}{63}\). \(\dfrac{7}{2}\)
= - \(\dfrac{205}{18}\)
a) 2/5 < x < 6/5
=> x = 1 ( =5/5 ) (vì x thuộc Z)
Vậy x = 1
b) 3/5 < 3/x < 3/2
=> 5 > x > 2
=> x thuộc { 4 ; 3 } (vì x thuộc Z)
Vậy ...
c) 3/8 + -11/8 < x < 22/9 + 5/18
=> -8/8 < x < 49/18
=>-1 < x < 2+13/18
=> x thuộc {0; 1; 2} ( vì x thuộc Z )
Vậy...
(1) CH4 + 2O2 -to-> CO2 + 2H2O (2) 3Fe + 2O2 -to->Fe3O4 (3) 2Mg + O2 -to-> 2 MgO (7) 2KMnO4 -to-> K2MnO4 + MnO2 + O2 (8) Fe + 2HCl --> FeCl2 + H2 (9) HgO + H2 -to-> Hg + H2O | (4) 2KClO3 -to,MnO2--> 2KCl + 3O2 (5) SO3 + H2O --> H2SO4 (6) 2Al + 3H2SO4 --> Al2(SO4)3 + 3H2 |
\(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
\(2Fe+O_2\underrightarrow{t^o}2FeO\)
\(2Mg+O_2\underrightarrow{t^o}2MgO\)
\(2KClO_3\underrightarrow{t^o}2KCl+3O_2\)
\(SO_3+H_2O\rightarrow H_2SO_4\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(2KMnO_4\underrightarrow{t^o}K_2MnO_4+MnO_2+O_2\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
1)\(\dfrac{2}{9}+\dfrac{-3}{4}+\dfrac{5}{30}\)
\(=\dfrac{2.20}{9.20}+\dfrac{-3.45}{4.45}+\dfrac{5.6}{30.6}\)
\(=\dfrac{40}{180}+\dfrac{-135}{180}+\dfrac{30}{180}\)
\(=\dfrac{40+\left(-135\right)+30}{180}\)
\(=\dfrac{-65}{180}\)
\(=\dfrac{-13}{36}\)
2)\(\dfrac{-7}{12}-\dfrac{11}{18}\)
\(=\dfrac{-7.3}{12.3}-\dfrac{11.2}{18.2}\)
\(=\dfrac{-21}{36}-\dfrac{22}{36}\)
\(=\dfrac{-21-22}{36}\)
\(=\dfrac{-43}{36}\)
3)\(\dfrac{7}{8}-\dfrac{-5}{16}\)
\(=\dfrac{7.2}{8.2}-\dfrac{-5}{16}\)
\(=\dfrac{14}{16}-\dfrac{-5}{16}\)
\(=\dfrac{14-\left(-5\right)}{16}\)
\(=\dfrac{19}{16}\)
4)\(\dfrac{3}{8}-\dfrac{-9}{10}-\dfrac{5}{16}\)
\(=\dfrac{3.10}{8.10}-\dfrac{-9.8}{10.8}-\dfrac{5.5}{16.5}\)
\(=\dfrac{30}{80}-\dfrac{-72}{80}-\dfrac{25}{80}\)
\(=\dfrac{30-\left(-72\right)-25}{80}\)
\(=\dfrac{77}{80}\)
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17+18 = 171 nhé
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17+18. = 171
\(\left(-12\cdot\dfrac{2}{7}+\dfrac{8}{9}:3\dfrac{1}{2}-\dfrac{2}{7}\cdot\dfrac{5}{18}\right)\cdot3\dfrac{1}{2}\)
\(=\left(-12\cdot\dfrac{2}{7}+\dfrac{8}{9}\cdot\dfrac{2}{7}-\dfrac{2}{7}\cdot\dfrac{5}{18}\right)\cdot\dfrac{7}{2}\)
\(=\left(-12+\dfrac{8}{9}-\dfrac{5}{18}\right)\cdot\dfrac{2}{7}\cdot\dfrac{7}{2}\)
\(=-\dfrac{205}{18}\cdot1\)
\(=-\dfrac{205}{18}\)