SS A vs B
\(A=\dfrac{54.107-53}{53.107+54}\)
\(B=\dfrac{135.169-133}{134.269+135}\)
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\(M=\dfrac{54.107-53}{53.107-54}=\dfrac{53\left(107-1\right)+107}{53\left(107-1\right)-1}=\dfrac{53.106-1+108}{53.106-1}=1+\dfrac{108}{53.106-1}\)
\(N=\dfrac{135.269-133}{134.269-135}=\dfrac{134\left(269-1\right)-1+270}{134\left(269-1\right)-1}=1+\dfrac{270}{134.268-1}\)
\(M-N=\dfrac{108}{53.106-1}-\dfrac{270}{134.268-1}\)
\(M-N=\dfrac{2}{2.53^2-1}-\dfrac{5}{8.67^2-1}>\dfrac{5}{10.53^2-1}-\dfrac{5}{8.67^2-1}>0\)
M>N
\(A=\dfrac{54.107-53}{53.107+54}=\dfrac{53.107+107-53}{53.107+54}=\dfrac{53.107+54}{53.107+54}=1\\ B=\dfrac{135.169-133}{134.269+135}=\dfrac{135.169-133}{134.269+134+1}=\dfrac{135.169-133}{134.270+1}=\dfrac{135.169-133}{268.135+1}< 1\\ Vậy:B< A\left(A=1\right).hay.A>B\)
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