Question

[dam khac quang anh]

Tim c thuoc Z sao cho 2n-3chia het cho n+1

Answer 1

[DanAlex]

Ta có: \(\frac{2n-3}{n+1}=\frac{2\left(n+1\right)-5}{n+1}=2-\frac{5}{n+1}\)

Để 2n - 3 chia hết cho n+1 thì \(\left(n+1\right)\in\)Ư(5)={1;-1;5;-5}

Ta có bảng sau:

n+1	1	-1	5	-5
n	0	-2	4	-6

Vậy n\(\in\){0;-2;4;-6}