Question

[Givemesome Flan]

  Giúp mình câu 21 22 23

Answer 1

[GV Nguyễn Trần Thành Đạt]

Câu 21:

\(C_nH_{2n-2}+AgNO_3+NH_3\rightarrow C_nH_{2n-3}Ag+NH_4NO_3\\ n_X=\dfrac{14-5,44}{108-1}=0,08\left(mol\right)=n_{kết.tủa}\\ M_{C_nH_{2n-3}Ag}=\dfrac{14}{0,08}=175\left(\dfrac{g}{mol}\right)=14n+107\\ \Leftrightarrow n=5\\ \Rightarrow CTPT.X:C_5H_8\\ CTCT:CH\equiv C-CH_2-CH_2-CH_3\\ CH_3-C\equiv C-CH_2-CH_3\\ CH\equiv C-CH\left(CH_3\right)-CH_3\)

Chọn C

Answer 2

[GV Nguyễn Trần Thành Đạt]

Câu 22: 

\(n_{C_2H_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\\ C_2H_2+2Br_2\rightarrow C_2H_2Br_4\\ n_{Br_2}=2.n_{C_2H_2}=2.0,1=0,2\left(mol\right)\\ m_{Br_2}=0,2.160=32\left(g\right)\\ Chọn.A\)