Tính:
a]2/9 + 3/9 b]3/15 + 5/5 c]4/25 + 3/100 d]4/9 + 3/2
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a)\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{-3}{5}.\dfrac{2}{7}+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{3}{7}.\dfrac{-2}{5}+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}.\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\dfrac{-3}{5}\)
=\(\dfrac{-2}{5}.1+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}+\dfrac{-3}{5}\)
=\(-\dfrac{5}{5}\) = -1
\(\dfrac{5}{9}.\dfrac{14}{17}+\dfrac{1}{17}.\dfrac{5}{9}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{5}{9}.\left(\dfrac{14}{17}+\dfrac{1}{17}\right)+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{5}{9}.\dfrac{15}{17}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{25}{51}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{691}{612}\)
a: =-15/24-18/24+60/24
=27/24=9/8
b: =6/12-9/12-10/12-7/12=-20/12=-5/3
c: =17/2+3/7-5/3=305/42
c: =-3-2/3-10/9-25/3-5/6
=-10-19/9-5/6
=-180/18-38/18-15/18=-233/18
a)\(1-2+3-4+5-6+7-8+8-9+9-10\)
=\(\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+\left(7-8\right)+\left(8-9\right)+\left(9-10\right)\)
\(=\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)\)
\(=\left(-1\right).6\)
\(=-6\)
b)\(1-2+3-4+...+99-100\)
\(=\left(1-2\right)+\left(3-4\right)+...+\left(99-100\right)\)}\(\left[\left(100-1\right):1+1\right]:2=50\)(cặp)
\(=\left(-1\right)+\left(-1\right)+\left(-1\right)+...+\left(-1\right)\)} 50 số (-1)
\(=\left(-1\right).50\)
\(=-50\)
c)\(1-3+5-7+9-11+13-15\)
\(=\left(1-3\right)+\left(5-7\right)+\left(9-11\right)+\left(13-15\right)\)
\(=\left(-2\right)+\left(-2\right)+\left(-2\right)+\left(-2\right)\)
\(=\left(-2\right).4\)
\(=-8\)
d)\(1-3+5-7+...-99+101\) (Đối với bài này, có vẻ đề sai, mình đã sửa lại rồi
\(=\left(1-3\right)+\left(5-7\right)+...+\left(97-99\right)+101\) } \(\left[\left(99-1\right):2+1\right]:2=25\)(cặp)
\(=\left(-2\right)+\left(-2\right)+\left(-2\right)+...+\left(-2\right)\) } 25 số (-2)
\(=\left(-2\right).25\)
\(=-50\)
e)\(-1-2-3-4-...-99-100\)
\(=\left(-1\right)+\left(-2\right)+\left(-3\right)+...+\left(-99\right)+\left(-100\right)\)
\(=\left[\left(-1\right)+\left(-100\right)\right]+\left[\left(-2\right)+\left(-99\right)\right]+...+\left[\left(-51\right)+\left(-50\right)\right]\) } \(\left[\left(100-1\right):1+1\right]:2=50\)(cặp) (phần này của đề bài, không thay được như (-100) hoặc (-1))
\(=\left(-100\right)+\left(-100\right)+\left(-100\right)+...+\left(-100\right)\)} 50 số (-100)
\(=\left(-100\right).50\)
\(=-5000\)
Bài 3:
a) 11 - (15 + 11) = x - (25 - 9)
=> 11 - 15 - 11 = x - 25 + 9
=> x = 9 - 25 + 15
=> x = -1
b) 2 - x = 17 - (-5)
=> 2 - x = 17 + 5
=> -x = 17 + 5 - 2
=> -x = 20
=> x = -20
c) x - 12 = (-9) - 15
=> x - 12 = -9 - 15
=> x = -9 - 15 + 12
=> x = -12
d) IxI - 7 = 9
=> IxI = 9 + 7
=> IxI = 16
=> x = 16 hay x = -16
e) 9 - 25 = (7 - x) - (25 + 7)
=> 9 - 25 = 7 - x - 25 - 7
=> x = 7 - 7 - 25 + 25 - 9
=> x = -9
Bài 4:
a) 25 . 46 + 54 . 25
= 25(46 + 54)
= 25.100
= 2500
b) 1200 : 25
= (25.48) : 25
= 25:25 . 48
= 1.48
= 48
c) 1356 - 998
= 1356 + 2 - 998 - 2
= 1358 - 1000
= 358
d) 117 + 57 - 17
= 117 - 17 + 57
= 100 + 57
= 157
Bài 5:
a) 34 . 315
= 34 + 15
= 319
b) 88 : 88
= 88 - 8
= 80
= 1
c) 100 - [120 - (15 - 5)2 ]
= 100 - (120 - 102)
= 100 - (120 - 100)
= 100 - 120 + 100
= 80
Bài 3 :
a, 11 - ( 15 + 11 ) = x - ( 25 - 9 )
11 - 26 = x - 16
- 15 = x - 16
x = - 15 + 16
x = 1
b, 2 - x = 17 - ( - 5 )
2 - x = 22
x = 2 - 22
x = - 20
c, x - 12 = - 9 - 15
x - 12 = - 24
x = - 24 + 12
x = - 12
d, | x | - 7 = 9
| x | = 9 + 7
| x | = 16
x = 16 hoặc - 16
e, 9 - 25 = ( 7 - x ) - ( 25 + 7 )
- 16 = 7 - x - 32
x = 7 - 32 + 16
x = - 9
Bài 4 :
25 x 46 + 54 x 25
= 25 x ( 46 + 54 )
= 25 x 100
= 2500
b, 1200 : 25
= 12 x 100 : 25
= 12 x 4
= 48
c, 1356 - 998
= 358
d, 117 + 57 - 17
= ( 117 - 17 ) + 57
= 100 + 57
= 157
Bài 5 :
a, 3^4 . 3^15
= 3^19
b, 8^8 : 8^8
= 1
c, 100 - [ 120 - ( 15 - 5 )^2 ]
= 100 - ( 120 - 100 )
= 100 - 20 = 80
bai 4 : a) = 2500
b)=48
c)=157
bai 5 : a)= 1162261467
b)=1
c)= 80
a: =-1+17/20=-3/20
b: =(28/60-33/60)*(-25/3)
=(-1/12)*(-25/3)=1/12*25/3=25/36
c: \(=\dfrac{1}{3}\cdot\dfrac{1}{3}=\dfrac{1}{9}\)
a)=\(\frac{-2.4}{5.7}+\frac{-3.2}{5.7}+\frac{-3}{5}\)
=\(\frac{-2.4}{5.7}+\frac{-2.3}{5.7}+\frac{-3}{5}\)
=\(\frac{-2}{5}\left(\frac{4+3}{7}\right)+\frac{-3}{5}\)
=\(\frac{-2}{5}.1+\frac{-3}{5}\)
=-1
b)
\(\dfrac{2}{9}+\dfrac{3}{9}=\dfrac{5}{9}\)
\(\dfrac{3}{15}+\dfrac{5}{5}=\dfrac{1}{5}+\dfrac{5}{5}=\dfrac{6}{5}\)
\(\dfrac{4}{25}+\dfrac{3}{100}=\dfrac{16}{100}+\dfrac{3}{100}=\dfrac{19}{100}\)
\(\dfrac{4}{9}+\dfrac{3}{2}=\dfrac{8}{18}+\dfrac{27}{18}=\dfrac{35}{18}\)
`2/9 +3/9=(2+3)/9=5/9`
`3/15 + 5/5 = 3/15 + 15/15 = 18/15`
`4/25 + 3/100= 16/100 + 3/100= 19/100`
`4/9 + 3/2= 8/18+ 27/18= 35/18`