tìm x biết |x-3|=5-x
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Bài 1:
Ta có: \(4-2\left(x+1\right)=2\)
\(\Leftrightarrow2\left(x+1\right)=2\)
\(\Leftrightarrow x+1=1\)
hay x=0
Bài 2:
Ta có: \(\left|2x-3\right|-1=2\)
\(\Leftrightarrow\left|2x-3\right|=3\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
Sửa đề : a) Tìm GTNN A
a) \(A=\left|x-5\right|+3\)có : \(\left|x-5\right|\ge0\Rightarrow\left|x-5\right|+3\ge0\)
\(\Leftrightarrow A\ge3\)dấu "=" xảy ra khi : \(\left|x-5\right|=0\Leftrightarrow x-5=0\Leftrightarrow x=5\)
Vậy GTNN A = 3 khi x = 5.
b) \(C=-\left|x+1\right|+5\)có : \(-\left|x+1\right|\le0\Rightarrow-\left|x+1\right|+5\le5\)
\(\Leftrightarrow C\le5\)dấu "=" xảy ra khi : \(-\left|x+1\right|=0\Leftrightarrow x+1=0\Leftrightarrow x=-1\)
Vậy GTLN C = 5 khi x = -1.
\(D=5-\left|2x+3\right|\)có : \(-\left|2x+3\right|\le0\Rightarrow5-\left|2x+3\right|\le5\)
\(\Leftrightarrow D\le5\)dấu "=" xảy ra khi : \(-\left|2x+3\right|=0\Leftrightarrow2x+3=0\Leftrightarrow x=-\frac{3}{2}\)
Vậy GTLN D = 5 khi x = -3/2.
c) \(\left|x-3\right|+\left|y+1\right|=0\)có \(\left|x-3\right|\ge0;\left|y+1\right|\ge0\Rightarrow\left|x-3\right|+\left|y+1\right|\ge0\)
\(\Rightarrow\hept{\begin{cases}\left|x-3\right|=0\\\left|y+1\right|=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=3\\y=-1\end{cases}}.\)
\(\frac{3}{5}+\frac{x}{35}=\frac{5}{7}\)
\(\frac{21}{35}+\frac{x}{35}=\frac{5}{7}\)
\(\frac{21+x}{35}=\frac{5}{7}\)
\(\Rightarrow7\left(21+x\right)=35x5\)
\(\Rightarrow147+7x=175\)
\(\Rightarrow7x=175-147=28\)
\(\Rightarrow x=\frac{28}{7}=4\)
5x(x-3)^2-5(x-1)^3+15(x+2)(x-2)=5
5x(x-3)^2-5(x-1)^3+15(x^2-2^2)=5
5x(x^2-6x+9)-5(x^3-3x^2+3x-1)+15x^2-60=5
5x^3-30x^2+45x-5x^3+15x^2-15x+5+15x^2-60=5
30x-55=5
30x=60
x=2
x = 4 nhé