tính
a)1032-[314-(314+32)]
b)12-11+15-27+11
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Bài 2: Thực hiện phép tính
a) (-5) + (-12) = -17 d) 12 - 11 +15 - 27 +11 = 2
b) (-9) +12 = 3 e) 1032 - [314 -(314 +32)] = 1000
c) 9 -12 = -3 g) [(-18) +(-7) ] + 15 = -10
a, -17 d, 12 - 11 + 15 - 27 + 11 e , 1032 - [314 - ( 314 + 32 )]
b , 3 = 12 - 11 + 15 - 27 = 1032 - [ 314 + ( -314) + 32 ]
c, -3 = -11 = 1032 - 32
= 1000
g , -10 ( CÂU A , B , C , G RẤT DỄ NÊN GIRL CHỈ VIẾT DÁP ÁN CÒN CÂU D VÀ E GIRL VIẾT CÂU BÀI LÀM + ĐÁP ÁN ĐÓA NHA NHỚ K VÀ KB NẾU CÓ THỂ
a) 1032 - [ 314 - ( 314 + 32)]
= 1032 - [ 314 - 314 -32 ]
= 1032 - [ 0 - 32 ]
= 1032 - (-32)
= 1032 + 32 =1064
b) 12 - 11 + 15 - 27 + 11
= 12 + (-11) + 15 +(-27) +11
= [ 12 + 15 + (-27)] + [ (-11) + 11]
= 0 + 0 = 0
a) 1032 - [314 - (314 + 32)]
=1032 - 314 + (314 + 32)
=1032 - 314 +314 + 32
=1032 +32=1064
b)12 - 11 + 15 - 27 +11
=12- 27 - 11 +11 +15
= -15 - 0 + 15
= -15+15 +0=0+0=0
1) \(\left(+15\right)+\left(+17\right)=15+17=32\)
2) \(\left(-3\right)+\left(-7\right)=-3-7=-\left(3+7\right)=-10\)
3) \(\left(-25\right)+\left(+4\right)=-25+4=-\left(25-4\right)=-21\)
4) \(\left(-6\right)+\left(-54\right)=-6-54=-\left(6+54\right)=-60\)
5) \(\left(-15\right)+20=20-15=5\)
6) \(\left(-5\right)+8+7+5\)
\(=\left(-5+5\right)+\left(8+7\right)\)
\(=15\)
7) \(\left(-8\right)+\left(-11\right)+\left(-2\right)\)
\(=\left[\left(-8\right)+\left(-2\right)\right]+\left(-11\right)\)
\(=\left(-10\right)+\left(-11\right)\)
\(=-21\)
8) \(15+\left(-5\right)+\left(-14\right)+\left(-16\right)\)
\(=\left[15+\left(-5\right)\right]+\left[\left(-14\right)+\left(-16\right)\right]\)
\(=10+\left(-30\right)\)
\(=-20\)
9) \(\left(-20\right)+\left(-14\right)+3+\left(-86\right)\)
\(=\left[\left(-20\right)+3\right]+\left[\left(-14\right)+\left(-86\right)\right]\)
\(=\left(-17\right)+\left(-100\right)\)
\(=-117\)
10) \(\left(-136\right)+123+\left(-264\right)+\left(-83\right)+240\)
\(=\left[\left(-136\right)+\left(-264\right)\right]+\left[123+\left(-83\right)\right]+240\)
\(=\left(-400\right)+40+240\)
\(=\left(-360\right)+240\)
\(=-120\)
11) \(\left(-596\right)+2001+1999+\left(-404+189\right)\)
\(=\left(-596\right)+2001+1999-404+189\)
\(=\left[\left(-596\right)-404\right]+\left(2001+189\right)+1999\)
\(=\left(-1000\right)+2190+1999\)
\(=1190+1999\)
\(=3189\)
12) \(314+\left(-153\right)+64+121+\left(-247\right)+218\)
\(=\left(314+64+121\right)+\left[\left(-153\right)+\left(-247\right)\right]+218\)
\(=\left(378+121\right)+\left(-400\right)+218\)
\(=499-400+218\)
\(=99+218\)
\(=317\)
\(\text{#}Toru\)
a: 200<314
=>1/200>1/314
=>17/200>17/314
b: 11/54=22/108
37<108
=>22/37>22/108
=>22/37>11/54
c: 141/893=3/19
159/901=3/17
mà 3/19<3/17
nên 141/893<159/901
d: 9/382=18/764=90/3820
6/257=18/771=90/3855
15/643=90/3858
3820<3855<3858
=>90/3820>90/3855>90/3858
=>9/382>6/257>15/643
a: 200<314
=>1/200>1/314
=>17/200>17/314
b: 11/54=22/108
37<108
=>22/37>22/108
=>22/37>11/54
c: 141/893=3/19
159/901=3/17
mà 3/19<3/17
nên 141/893<159/901
d: 9/382=18/764=90/3820
6/257=18/771=90/3855
15/643=90/3858
3820<3855<3858
=>90/3820>90/3855>90/3858
=>9/382>6/257>15/643
a ) 4 7 + 2 7 + 1 7 + 3 4 + 5 4 = 3 b ) − 5 7 + − 2 7 + − 1 5 + 3 4 + 1 4 = − 1 5
c ) 5 13 + 8 13 + − 5 7 + − 20 41 + − 21 41 = − 5 7 d ) 1 28 + 3 28 + 3 14 + − 1 14 + − 1 7 = 1 7 e ) 1 2 + − 1 2 + − 2 3 + 2 3 + 3 4 + − 3 4 + − 4 5 + 4 5 + 5 6 + − 5 6 = 0
Bài 2:
a) 37 x 7 - 17 x 11 + 13 x 37 + 17 x 21
b) 55 x 52 : 54 - 28 : 24
c) 311 x 12 + 312 x 5 - 314
`#040911`
`a)`
\(37 \times 7 - 17 \times 11 + 13 \times 37 + 17 \times 21\)
`= 37 \times (7 + 13) + 17 \times (21 - 11)`
`= 37 \times 20 + 17 \times 10`
`= 10 \times (37 \times 2 + 17)`
`= 10 \times 91`
`= 910`
`b)`
\(5^5 \times 5^2 \div 5^4 - 2^8 \div 2^4\)
`=`\(5^{5+2-4}-2^{8-4}\)
`= 5^3 - 2^4`
`= 125 - 16`
`= 109`
`c)`
\(3^{11}\times12+3^{12}\times5-3^{14}\)
`=`\(3^{11}\times\left(12+3\times5-3^3\right)\)
`=`\(3^{11}\times\left(12+15-27\right)\)
`=`\(3^{11}\times0=0\)
a) = 259 - 187 + 481 + 357
= 910
b) = 57 : 54 - 24
= 53 - 24
= 125 - 16
= 109
Ta có : \(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.8}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=3.2\)
\(\Rightarrow\) \(A=6\)
Vậy A = 6
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a, 15 . { 32 : [ 6 - 5 + 5 ( 9 : 3 ) ] + 3 } - 2018 0
= 15.{32:[1+15]+3}–1
= 15.5–1
= 74
b, 25 . { 2 7 : [ 12 - 4 + 2 2 . 16 : 2 3 ] - 2 4 }
= 25.{128:[8+4.2]–16}
= 25.24
= 600
c, 2019 . { 101 - 1000 : [ 2 2 . 2 3 + 5 6 : 5 3 - 6 2 : 11 - 2018 0 ] }
= 2019.{101–1000:[(32+125–36):11–1]}
= 2019.{101–1000:[121:11–1]}
= 2019.{101–1000:10}
= 2019.1
= 2019
a) 1032-[314-(314+32)]
= 1032-[314-346]
= 1032- (-32)
= 1064
b) 12-11+15-27+11
= 1+15-27+11
= 16 - 27 + 11
= (-11) + 11
= 0