(3x+13).23_24=22.3.23
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BK
1
TA
1 tháng 11 2019
\(\left(\sqrt{7+3x}-4\right)+\left(\sqrt{13-3x}-2\right)+5.\left(\sqrt{\left(7+3x\right)\left(13-3x\right)}-8\right)=0\)
=) \(\frac{7+3x-16}{\sqrt{7+3x}+4}+\frac{13-3x-4}{\sqrt{13-3x}+2}+5.\left(\sqrt{91+18x-9x^2}-8\right)=0\)
=) \(\frac{3\left(x-3\right)}{\sqrt{7+3x}+4}+\frac{3\left(3-x\right)}{\sqrt{13-3x}+2}+\frac{5\left(27+18x-9x^2\right)}{\sqrt{91+18x-9x^2}+8}=0\)
=) \(\frac{3\left(x-3\right)}{\sqrt{7+3x}+4}-\frac{3\left(x-3\right)}{\sqrt{13-3x}+2}-\frac{45\left(x+1\right)\left(x-3\right)}{\sqrt{91+18x-9x^2}+8}=0\)
=) đến đây chắc là tự làm đc rồi
HC
1
16 tháng 11 2022
Đặt \(\sqrt{7+3x}=a;\sqrt{13-3x}=b\)
=>a+b+5ab=46
=>(a+b)^2=46-5ab
=>a^2+b^2+2ab=2116-460ab+25a^2b^2
=>25a^2b^2-460ab+2116=7+3x+13-3x+2ab
=>25a^2b^2-462ab+2096=0
=>\(\left[{}\begin{matrix}ab=\dfrac{262}{25}\\ab=8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left(7+3x\right)\cdot\left(13-3x\right)=109.8304\\\left(7+3x\right)\left(13-3x\right)=64\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}91-21x+39x-9x^2=109.8304\\91-21x+39x-9x^2=64\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}-9x^2+18x-18.8304=0\\-9x^2+18x+27=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
HC
0
PT
2
11 tháng 5 2021
a)5-(13-3x)=109-(32+109)
5-(13-3x)=-32
13-3x =37
3x =-24
3x =-6
11 tháng 5 2021
a)5-(13-3x)=109-(32+109)
5-13+3x =109-32-109
-8+3x=-32
3x=-32-(-8)
3x=-24
x=-24:3
x=-8
b)|3x-6|+(x-22)=0
(3x-6)+(x-22)=0
3x-6+x-22=0
3x+x=0+6+22
4x=10
x=\(\dfrac{5}{2}\)
c)/7-2x/=-13-5.(-8)
|7-2x|=27
⇒7-2x=27 hoặc 7-2x=-27
x=-10 hoặc x=-17
L
26 tháng 10 2019
\(a)xy+3x-2y=11\)
\(\Leftrightarrow xy+3x-2y-6=5\)
\(\Leftrightarrow x\left(y+3\right)-2\left(y+3\right)=5\)
\(\Leftrightarrow\left(y+3\right)\left(x-2\right)=5\)
\(\Leftrightarrow\hept{\begin{cases}y+3=-1\\x-2=-5\end{cases}}\Leftrightarrow\hept{\begin{cases}y=-4\\x=-3\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}y+3=1\\x-2=5\end{cases}}\Leftrightarrow\hept{\begin{cases}y=-2\\x=7\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}y+3=-5\\x-2=-1\end{cases}}\Leftrightarrow\hept{\begin{cases}y=-8\\x=1\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}y+3=5\\x-2=1\end{cases}}\Leftrightarrow\hept{\begin{cases}y=2\\x=3\end{cases}}\)
L
26 tháng 10 2019
\(b)2x^2-2xy+x-y=12\)
\(\Leftrightarrow2x\left(x-y\right)+\left(x-y\right)=12\)
\(\Leftrightarrow\left(x-y\right)\left(2x+1\right)=12\)
\(\Rightarrow\left(x-y\right);\left(2x+1\right)\inƯ\left(12\right)\)
\(\RightarrowƯ\left(12\right)\in\left\{-1;1;-2;2;-3;3;-4;4;-6;6;-12;12\right\}\)
Vì 2x+1 luôn lẻ
\(\Rightarrow2x+1\in\left\{-1;1;-3;3\right\}\)
\(\Leftrightarrow\hept{\begin{cases}2x+1=-1\\x-y=-12\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-1\\y=11\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}2x+1=1\\x-y=12\end{cases}}\Leftrightarrow\hept{\begin{cases}x=0\\y=-12\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}2x+1=-3\\x-y=-4\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-2\\y=2\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}2x+1=3\\x-y=4\end{cases}}\Leftrightarrow\hept{\begin{cases}x=1\\y=-3\end{cases}}\)
10 tháng 8 2016
\(\left[5^3.\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)
\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)
\(\left[5^3\left(3x+2\right)\right]:13=\frac{3125}{13}\)
\(\left[5^3\left(3x+2\right)\right]=3125\)
\(3x+2=3125:5^3\)
\(3x+2=25\)
\(3x=25-2\)
\(3x=23\)
\(x=\frac{23}{3}\)
10 tháng 8 2016
\(5^3.\left(3x+2\right):13=5^5:\left(13^5:13^4\right)\)
\(5^3.\left(3x+2\right):13=3125:13\)
\(5^3.\left(3x+2\right):13=\frac{3125}{13}\)
125 . ( 3x + 2 ) : 13 =\(\frac{3125}{13}\)
125 . ( 3x + 2 ) =\(\frac{3125}{13}.\frac{13}{1}=3125\)
3x + 2 = 3125 : 125
3x + 2 = 25
3x = 25 -2
3x = 23
x = 23 : 3
x = \(\frac{23}{3}\)
19 tháng 11 2016
\(5^3\left(3x+2\right)\div13=10^3\div\left(13^5\div13^4\right)\)
\(\Rightarrow125\left(3x+2\right)\div13=1000\div13\)
\(\Rightarrow125\left(3x+2\right)=1000\)
\(\Rightarrow3x+2=1000\div125\)
\(\Rightarrow3x+2=8\)
\(\Rightarrow3x=8-2\)
\(\Rightarrow3x=6\Rightarrow x=6\div3\Rightarrow x=2\)
Vậy : x = 2
8 tháng 8 2016
\(\left[5^3\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)
\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)
\(5^3\left(3x+2\right)=5^5:13.13\)
\(5^3\left(3x+2\right)=5^5\)
\(3x+2=5^5:5^3\)
\(3x+2=25\)
\(3x=25-2\)
\(3x=23\)
\(\Rightarrow x=\frac{23}{3}\)
KK
1
15 tháng 3 2017
\(a,\frac{7}{3}x+5=\frac{9}{6}x-7\)
\(\frac{7}{3}x-\frac{9}{6}x=-7-5\)
\(\left(\frac{7}{3}-\frac{9}{6}\right).x=-12\)
\(\frac{5}{6}.x=-12\)
\(x=\left(-12\right):\frac{5}{6}\)
\(x=-\frac{72}{5}\)
\(b,3x+\frac{6}{4}=5-\frac{7x}{6}\)
\(3x+\frac{7x}{6}=5-\frac{6}{4}\)
\(\left(3+\frac{7}{6}\right).x=\frac{7}{2}\)
\(\frac{25}{6}.x=\frac{7}{2}\)
\(x=\frac{7}{2}:\frac{25}{6}\)
\(x=\frac{21}{25}\)
\(c,\frac{12}{5}x+6=\frac{17}{3}x+12\)
\(\frac{12}{5}x-\frac{17}{3}x=12-6\)
\(-\frac{49}{15}x=6\)
\(x=6:\left(-\frac{49}{15}\right)\)
\(x=-\frac{90}{49}\)
\(d,6\left(3x+7\right)=12\left(2x-4\right)\)
\(18x+42=24x-48\)
\(18x-24x=-48-42\)
\(-6x=-90\)
\(x=15\)
\(e,13\left(2x-9\right)=8\left(3x-13\right)\)
\(26x-117=24x-104\)
\(26x-24x=-104+117\)
\(2x=13\)
\(x=\frac{13}{2}\)
(3x+13).23-24=22.3.23
(3x+13).23-24=276
(3x+13).23=292
3x+13=36,5
3x=23,5
x=7,8