tìm x biết : ( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ( x + 10 ) = 62
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\(\left(x+1\right)+\left(x+4\right)+\left(x+7\right)+\left(x+10\right)=62\)
\(\Rightarrow x+1+x+4+x+7+x+10=62\)
\(\Rightarrow4x+22=62\)
\(\Rightarrow4x=40\)
\(\Rightarrow x=10\)
(x+1)+(x+4)+(x+7)+(x+10)=62
( x + x + x + x ) + ( 1 + 4 + 7 + 10 ) = 62
4x + 22 = 62
4x = 62 - 22
4x = 40
x = 40 : 4
x = 10
(x + 1) + (x + 4) + (x + 7) + (x + 10) = 62
x + 1 + x + 4 + x + 7 + x + 10 = 62
4x + 22 = 62
4x = 40
=> x = 40 / 10 = 4
\(x\) + \(x\) + \(x\) + \(x\) = 100
\(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\)1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1 = 100
\(x\) \(\times\) ( 1 + 1 + 1 + 1 + 1 ) = 100
\(x\) \(\times\) 5 = 100
\(x\) = 100 : 5
\(x\) = 20
\(x\) + \(x\) + \(x\) + \(x\) \(\times\) 5 = 200
\(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\)1 + \(x\) \(\times\) 5 = 200
\(x\) \(\times\) ( 1 + 1 + 1 + 5) = 200
\(x\) \(\times\) 8 = 200
\(x\) = 200 : 8
\(x\) = 25
(\(x\) + 1) + (\(x\) + 4) + ( \(x\) + 7) + (\(x\) + 10) = 62
\(x\) + 1 + \(x\) + 4 + \(x\)+ 7 + \(x\) + 10 = 62
( \(x\) + \(x\) + \(x\) + \(x\) ) + ( 1 + 4 + 7 + 10) = 62
( \(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1) + 22 = 62
\(x\) \(\times\) ( 1 + 1 + 1 + 1) + 22 = 62
\(x\) \(\times\) 4 + 22 = 62
\(x\) \(\times\) 4 = 62 - 22
\(x\) \(\times\) 4 = 40
\(x\) = 40 : 4
\(x\) = 10
( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ( x + 10 ) = 62
( x + x + x + x ) + ( 1 + 4 + 7 + 10 ) = 62
4x + 22 = 62
4x = 62 - 22
4x = 40
x = 40 : 4
x = 10
a: \(\Leftrightarrow x\cdot\left(\dfrac{37}{99}+\dfrac{62}{99}\right)=10\)
=>x=10
b: \(\Leftrightarrow x:\dfrac{4}{9}=\dfrac{4}{33}:\dfrac{5}{3}=\dfrac{4}{33}\cdot\dfrac{3}{5}=\dfrac{4}{55}\)
\(\Leftrightarrow x=\dfrac{16}{495}\)
(x+1)+(x+4)+(x+7)+(x+10)=62
=>4x+22=62
=>4x=62-22
=>4x=40
=>x=10
t tôi nha bn
x+(1+4+7+10)=62
x+22=62
x=62-22
x=40