104,5 x X - 14,1 x X + 9,6 x X = 25
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\(104,5\cdot x-14,1\cdot x-9,6\cdot x=25\)
\(\Rightarrow x\cdot\left(104,5-14,1-9,6\right)=25\)
\(\Rightarrow x\cdot80,8=25\)
\(\Rightarrow x=25\div80,8=\frac{125}{404}\)
Vậy x = \(\frac{125}{404}\)
\(104,5.x-14,1.1+9,6.x=25,6.9,6\)
\(\left(104,5-14,1+9,6\right).x=245,76\)
\(100.x=245,76\)
\(x=245,76:100\)
\(x=2,4576\)
Vậy \(x=2,4576\)
Chú ý dấu . là nhân
k mình nha
#)Giải :
a) \(\frac{2xX-4,36}{0,125}=\)0,25 x 42,9 - 11,7 x 0,25 + 0,25 x 0,8
\(\frac{2xX-4,36}{0,125}=\)0,25 x ( 42,9 - 11,7 + 0,8 )
\(\frac{2xX-4,36}{0,125}=\)0,25 x 32
\(\frac{2xX-4,36}{0,125}=8\)
\(2xX-4,36=8x0,125\)
\(2xX-4,36=1\)
\(2xX=1+4,36\)
\(2xX=5,36\)
\(X=5,36:2\)
\(X=2,68\)
#~Will~be~Pens~#
#)Giải :
1.
Ta có : \(\frac{n+1}{n+2}>\frac{n}{n+2}>\frac{n}{n+3}\)
\(\Rightarrow\frac{n+1}{n+2}>\frac{n}{n+3}\)
2.
a) \(x\left(104,5-14,1+9,6\right)=25\)
\(x\times100=25\)
\(x=25\div100\)
\(x=0,25\)
Bài 1 : Ta có :\(\frac{n+1}{n+2}>\frac{n}{n+2}>\frac{n}{n+3}\)
\(\Leftrightarrow\frac{n+1}{n+2}>\frac{n}{n+3}\)
Bài 2 : \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)
\(\Leftrightarrow\left[104,5-14,1+9,6\right]\cdot x=25\)
\(\Leftrightarrow100\cdot x=25\)
\(\Leftrightarrow x=\frac{1}{4}\)
\(1+2+3+4+...+x=210\)
Số số hạng của dãy là : \((x-1):1+1=x\) số
Cho nên tổng của dãy đó là : \(\frac{x(x+1)}{2}=210\)
\(\Leftrightarrow x(x+1)=420\)
\(\Leftrightarrow x(x+1)=20\cdot21\)
\(\Leftrightarrow x=20\)
\(x-\frac{3}{4}=1-\frac{5}{6}\)
\(\Leftrightarrow x-\frac{3}{4}=\frac{1}{6}\)
\(\Leftrightarrow x=\frac{1}{6}+\frac{3}{4}=\frac{11}{12}\)
\(104,5.y+14,1.9,6.y=25\)
\(104,5.y+135,36.y=25\)
\(y.\left(104,5+135,36\right)=25\)
\(y.239,86=25\)
\(y=25\div239,86\)
\(y=\frac{1250}{11993}\)
y là số vô tỉ nên chị viết thành phân số em nhé!
\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)
\(\Leftrightarrow2x-4,36=1\)
\(\Leftrightarrow2x=5,36\)
\(\Leftrightarrow x=2,68\)
b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)
Bài 1:
a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)
\(\frac{2\cdot x-4,36}{0,125}=8\)
\(2\cdot x-4,36=8\cdot0,125\)
\(2\cdot x-4,36=1\)
\(2\cdot x=1+4,36\)
\(2\cdot x=5,36\)
\(x=\frac{5,36}{2}=2,68\)
b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)
\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)
\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)
\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)
\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)
Bài 2:
a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )
\(x+5,2=4,7\cdot3,2+0,5\)
\(x+5,2=15,54\)
\(x=15,54-5,2=10,34\)
b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)
Bài 3:
a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)
\(x\cdot\left(104,5-14,1+9,6\right)=25\)
\(x\cdot100=25\)
\(x=\frac{25}{100}=\frac{1}{4}=0,25\)
b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)
a,
104,4 . x -14,1 . x + 9,6 . x =25
x(104,4 - 14,1 + 9,6 ) = 25
x.99,9 = 25
x = \(\frac{250}{999}\)
b)
\(\frac{2009.2010+2000}{2011.2010-2020}=\frac{2009.2010+2000}{\left(2009+2\right).2010-2020}\)
\(=\frac{2009.2010+2000}{2009.2010+2.2010-2020}\)
\(=\frac{2009.2010+2000}{2009.2010+4020-2020}\)
\(=\frac{2009.2010+2000}{2009.2010+2000}\)
\(=1\)
104,5 x X - 14,1 x X + 9,6 x X = 25
X x ( 104,5 - 14,1 + 9,6 ) = 25
X x 100 = 25
X = 25 : 100
X = 0,25
104,5 x X - 14,1 x X + 9,6 x X = 25
X x ( 104,5 - 14,1 + 9,6 ) = 25\(^{^{ }x}\)
X x 100 = 25
X = 25 : 100
= 0,25