So sánh p/s 5/-21 và -7/30
giúp mình với ạ<3
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: -91/104=-7/8=-21/24
-5/6=-20/24
=>-91/104<-5/6
b: -15/21=-5/7
-36/44=-9/11
5/7=1-2/7; 9/11=1-2/11
mà 2/7>2/11
nên 5/7<9/11
=>-15/21>-36/44
a: 4/5=1-1/5
5/6=1-1/6
mà 1/5>1/6
nên 4/5<5/6
b: 3/7=9/21>5/21
c: 13/12<14/12=7/6
\(\frac{75}{100}=\frac{3}{4}=\frac{6}{8}< \frac{7}{8}\)
\(\frac{7}{8}< 1< \frac{3}{2}\)
\(\frac{60}{108}=\frac{5}{9}=\frac{15}{27}>\frac{15}{37}\)
\(\frac{15}{37}=\frac{30}{74}< \frac{31}{74}< \frac{31}{54}\)
\(\frac{0}{16}=\frac{0}{21}\)
Xét \(1-\frac{1965}{1967}=\frac{2}{1967}>\frac{2}{1975}=1-\frac{1973}{1975}\Rightarrow\frac{1965}{1967}< \frac{1973}{1975}\)
a.
$5^{75}=(5^5)^{15}=3125^{15}$
$7^{60}=(7^4)^{15}=2401^{15}$
Mà $3125> 2401$ nên $5^{75}> 7^{60}$
b.
$3^{21}=3.3^{20}=3.9^{10}$
$2^{31}=2.2^{30}=2.8^{10}< 3. 9^{10}$
$\Rightarrow 3^{21}> 2^{31}$
\(\dfrac{21}{36}-\left(-\dfrac{11}{30}\right)=\dfrac{7}{12}+\dfrac{11}{30}=\dfrac{7.5+11.2}{60}=\dfrac{57}{60}=\dfrac{19}{20}\\ ----\\\dfrac{-4}{8}+\left(-\dfrac{3}{10}\right)=\dfrac{-1}{2}-\dfrac{3}{10}=\dfrac{-1.5-3}{10}=\dfrac{-8}{10}=-\dfrac{4}{5}\\ ----\\ \dfrac{7}{12}-\left(-\dfrac{9}{20}\right)=\dfrac{7}{12}+\dfrac{9}{20}=\dfrac{7.5+9.3}{60}=\dfrac{62}{60}=\dfrac{31}{30}\\ ---\\ \dfrac{-2}{5}+\left(-\dfrac{11}{30}\right)=-\dfrac{2}{5}-\dfrac{11}{30}=\dfrac{-2.6-11}{30}=-\dfrac{29}{30}\)
a) 528 = (52)14 = 2514
Vì 2514 < 2614 nên 528 < 2614
b) 530 = (53)10 = 12510
Vì 12510 > 12410 nên 530 > 12410
c) 421 = (43)7 = 647
Vì 647 = 647 nên 421 = 647
Mong mn ủng hộ mk
\(a,5^{28}=\left(5^2\right)^{14}=25^{14}< \)\(26^{14}\)
\(\Rightarrow5^{28}< 26^{14}\)
\(b,5^{30}=\left(5^3\right)^{10}=125^{10}>124^{10}\)
\(\Rightarrow5^{30}>124^{10}\)
\(c,4^{21}=\left(4^3\right)^7=64^7\)
\(\Rightarrow4^{21}=64^7\)
1. a, \(\frac{6}{7}\)=\(\frac{60}{70}\);\(\frac{11}{10}\)=\(\frac{77}{70}\)
vì \(\frac{60}{70}\)<\(\frac{77}{70}\)nên \(\frac{6}{7}\)<\(\frac{11}{10}\)
b, \(\frac{-5}{17}\)<0<\(\frac{2}{7}\)
c, \(\frac{419}{-723}\)<0<\(\frac{-697}{-313}\)
2.
Ta có :\(\frac{2}{6}\)=\(\frac{20}{60}\);\(\frac{5}{12}\)=\(\frac{25}{60}\);\(\frac{4}{15}\)=\(\frac{16}{60}\);\(\frac{8}{20}\)=\(\frac{24}{60}\);\(\frac{10}{30}\)=\(\frac{20}{60}\)
Vì \(\frac{16}{60}\)<\(\frac{20}{60}\)<\(\frac{24}{60}\)<\(\frac{25}{60}\)nên \(\frac{4}{15}\)<\(\frac{2}{6}\)=\(\frac{10}{30}\)<\(\frac{8}{20}\)<\(\frac{5}{12}\)