chứng minh 5^61 + 25^31 + 125^21 chia hết cho 3
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\(5^{61}+25^{31}+125^{21}=5^{61}+5^{62}+5^{63}\)
\(=5^{61}\left(1+5+5^2\right)=5^{61}.31\)
Chia het cho 31
5^61 + 25^31 + 125^21
= 5^61 + 5^62 + 5^63
= 5^61 x (1+5+25)
= 5^61 x 31 chia hết 31
5^61 + 25^31 + 125^21
= 5^61 + 5^62 + 5^63
= 5^61 x (1+5+25)
= 5^61 x 31 chia hết 31
\(A=5^{61}+25^{31}+125^{21}\)
\(\Rightarrow A=5^{61}+\left(5^2\right)^{31}+\left(5^3\right)^{21}\)
\(\Rightarrow A=5^{61}+5^{62}+5^{63}\)
\(\Rightarrow A=5^{61}\left(1+5+5^2\right)\)
\(\Rightarrow A=5^{61}.31⋮31\)
\(\Rightarrow A⋮31\)
Vậy \(A⋮31\)
\(A=5^{61}+25^{31}+125^{21}\)
\(A=5^{61}+\left(5^2\right)^{31}+\left(5^3\right)^{21}\)
\(A=5^{61}+5^{62}+5^{63}\)
\(A=5^{61}\left(1+5+5^2\right)\)
\(A=5^{61}\cdot31⋮31\left(đpcm\right)\)
a ) \(5^{61}+25^{31}+125^{21}=5^{61}+5^{62}+5^{63}=5^{61}\left(1+5+25\right)=5^{61}.31⋮31\)(đpcm)
b ) \(6^3+2.6^2+3^3=2^3.3^3+2^3.3^2+3^3=3^2\left(8.3+8+3\right)=3^2.35⋮35\) (đpcm)
Vậy ........
561 + 2531 + 12521 = 561 + (52)31 + (53)21 = 561 + 562 + 563 = 561 + 561 . 5 + 561 . 52 = 561(1 + 5 + 52)
= 561 . 31
có: 155 = 31 . 5
=> 561 . 31 chia hết cho 31 . 5
b) \(\left(x-\dfrac{3}{5}\right)^2=4\)
\(\Leftrightarrow\sqrt{\left(x-\dfrac{5}{3}\right)^2}=\sqrt{4}\)
\(\Leftrightarrow\left|x-\dfrac{3}{5}\right|=2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{5}=2\\x-\dfrac{3}{5}=-2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{13}{5}\\x=-\dfrac{7}{5}\end{matrix}\right.\)
vậy
\(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)\cdot\cdot\cdot\left(\frac{1}{2009}-1\right)\)
\(=\frac{-1}{2}\cdot\frac{-2}{3}\cdot\cdot\cdot\cdot\frac{-2008}{2009}\)
\(=\frac{\left(-1\right)\cdot\left(-2\right)\cdot\cdot\cdot\left(-2008\right)}{2\cdot3\cdot\cdot\cdot2009}\)
\(=\frac{1\cdot2\cdot\cdot\cdot2008}{2\cdot3\cdot\cdot\cdot2009}\)
\(=\frac{1}{2009}\)
5^61+25^31+125^21 =5^61+5^62+5^63 =5^61(1+5+5^2) =5^61.31
Không chia hết cho 3 đâu bạn, chỉ 31 thôi