X - 637 = 125 x 6
X + 174 = 3168 : 9
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a, Ta có: 3 x = 3 2 nên x = 2
b, Ta có: 5 x = 5 3 nên x = 3
c, Ta có: 3 x + 1 = 3 2 nên x +1 = 2, do đó x = 1
d, Ta có: 6 x - 1 = 6 2 nên x - 1 = 2, đo đó x = 3
e) Ta có: 3 2 x + 1 = 3 3 nên 2x +1 = 3, do đó x = 1
f) Ta có: x 50 = x nên x 50 - x = 0 , do đó x x 49 - 1 = 0 = 0
Vì thế x = 0 hoặc x = 1
a, 324 + 68 - 174 + 93 + 132
\(=\left(324-174\right)+\left(68+132\right)+93\)
\(=150+200+93\)
\(=443\)
b, 68 x 125 x 16 x 5
\(=68x5x25x80\)
\(=1700x400\)
\(=680000\)
\(\dfrac{637\times527-189}{526\times637+448}\)
\(=\dfrac{637\times\left(526+1\right)-189}{526\times637+448}\)
\(=\dfrac{637\times526+637-189}{526\times637+448}\)
\(=\dfrac{637\times526+448}{526\times637+448}\)
\(=\dfrac{1}{1}\)
\(=1\)
526 x 637 + 448 335510
---------------------------- = ------------------------ = 1
637 x 527 -189 335510
Hok tốt nhé
# EllyNguyen #
a) \(x^2-xz-9y^2+3yz\)
\(=\left(x^2-9y^2\right)-\left(xz-3yz\right)\)
\(=\left(x-3y\right)\left(x+3y\right)-z\left(x-3y\right)\)
\(=\left(x-3y\right)\left(x+3y-z\right)\)
c) \(x^3+2x^2-6x-27\)
\(=\left(x^3-27\right)+\left(2x^2-6x\right)\)
\(=\left(x-3\right)\left(x^2-3x+9\right)+2x\left(x-3\right)\)
\(=\left(x-3\right)\left(x^2-3x+9+2x\right)\)
\(=\left(x-3\right)\left(x^2-x+9\right)\)
\(\frac{637\times527-189}{526\times637+448}\)
\(=\frac{637\times\left(526+1\right)-189}{526\times637+448}\)
\(=\frac{637\times526+637-189}{526\times637+448}\)
\(=\frac{637\times526+448}{526\times637+448}\)
\(=1\)
\(\frac{677\times874+251}{678\times874-623}\)
\(=\frac{677\times874+251}{\left(677+1\right)\times874-623}\)
\(=\frac{677\times874+251}{677\times874+874-623}\)
\(=\frac{677\times874+251}{677\times874+251}\)
\(=1\)
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X - 637 = 125 x 6
X= X - 637 = 750
X= 750 + 637
X= 1387
X + 174 = 3168 : 9
X= X + 174 = 352
X= 352 - 174
X = 178
x - 637 = 750
x = 750 + 637
x = 1387
x + 174 = 352
x = 352 - 174
x = 178