mn giúp e vơi
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37. What is the price of the bicycle? (How much)
=> How much does the bicycle costs?
38. The tea doesn't taste the same as the one I usually drink. (from)
=> The tea tastes diferrently from the one I usually drink.
39. I really like listening to pop ballad songs. (fond)
=> I'm really fond of listening to pop ballad songs.
40. I want some iced tea because I am hot. (so)
=> I am hot so I want some iced tea.
M P N 3 cm 4 cm 5 cm E Tia đối tia NP
bạn thấy tam giác ENM rồi đấy
<Bạn tự tóm tắt nha>
Đổi 6m/s=21,6km/h
Vận tốc trung bình của xe là
\(v_{tb}=\dfrac{t\left(\dfrac{3v_1}{4}+\dfrac{1v_2}{4}\right)}{t}=\dfrac{3\cdot21,6}{4}+\dfrac{v_2}{4}\Rightarrow\dfrac{64,8}{4}+\dfrac{v_2}{4}=35\Rightarrow v_2=75,2\left(\dfrac{km}{h}\right)\)
Vậy ...
\(ĐK:x\ge\dfrac{1}{2}\\ PT\Leftrightarrow4\sqrt{2x-1}+3\sqrt{2x-1}=4\\ \Leftrightarrow\sqrt{2x-1}=\dfrac{4}{7}\\ \Leftrightarrow2x-1=\dfrac{16}{49}\\ \Leftrightarrow x=\dfrac{65}{98}\left(tm\right)\)
\(\sqrt{32x-16}+\sqrt{18x-9}=4\) (ĐKXĐ: x≥\(\dfrac{1}{2}\))
⇔ \(\sqrt{16\left(2x-1\right)}+\sqrt{9\left(2x-1\right)}=4\)
⇔ 4\(\sqrt{2x-1}\)\(+3\sqrt{2x-1}\)= 4
⇔ 7\(\sqrt{2x-1}=4\)
⇔ \(\sqrt{2x-1}=\dfrac{4}{7}\)
⇔ \(2x-1=\dfrac{16}{49}\)
⇔ 2x = \(\dfrac{65}{49}\)
⇔ x = \(\dfrac{65}{98}\) (TM)
Vậy x = \(\dfrac{65}{98}\)
`1+1/3=4/3`
`=>1/(1+1/3)=1:4/3=3/4`
`=>B=(1-1/3+3/4)/(1-1/3-3/4)`
`=(2/3+3/4)/(2/3-3/4)`
`=17/12:(-1/12)`
`=-17`