Tìm x:x/6 x 5/8 = 5/12
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\(x-\dfrac{4}{12}=-\dfrac{5}{6}\)
⇔\(x-\dfrac{1}{3}=-\dfrac{5}{6}\)
⇔\(x=-\dfrac{1}{2}\)
\(x=\dfrac{4}{5}\times\dfrac{4}{3}\)
\(x=\dfrac{16}{15}\)
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\(x=\dfrac{5}{9}\times\dfrac{3}{8}\)
\(x=\dfrac{5}{24}\)
\(\dfrac{x}{5}=\dfrac{5}{6}-\dfrac{19}{30}\)
\(\Leftrightarrow\dfrac{x}{5}=\dfrac{25}{30}-\dfrac{19}{30}=\dfrac{6}{30}=\dfrac{1}{5}\)
\(\Leftrightarrow x=1\)
Ta có : \(\dfrac{x}{5}=\dfrac{5}{6}+\left(-\dfrac{19}{30}\right)=\dfrac{25}{30}-\dfrac{19}{30}=\dfrac{1}{5}\)
\(\Leftrightarrow5x=5\)
\(\Leftrightarrow x=1\)
Vậy ...
\(x\times\dfrac{4}{5}=3-\dfrac{2}{5}\)
\(x\times\dfrac{4}{5}=\dfrac{13}{5}\)
\(x=\dfrac{13}{5}:\dfrac{4}{5}\)
\(x=\dfrac{13}{5}\times\dfrac{5}{4}\)
\(x=\dfrac{13}{4}\)
Chiều dài HCN là :
\(\dfrac{5}{6}:\dfrac{2}{3}=\dfrac{5}{4}\left(m\right)\)
Chu vi HCN là :
\(\left(\dfrac{5}{4}+\dfrac{2}{3}\right)\times2=\dfrac{23}{6}\left(m\right)\)
Đ/s :...
\(x\times\dfrac{4}{5}=\dfrac{13}{5}\\ x=\dfrac{13}{5}\div\dfrac{4}{5}\\ x=\dfrac{13}{4}\)
\(CD=\dfrac{5}{6}\div\dfrac{2}{3}=\dfrac{5}{4}\\ P=\left(\dfrac{5}{4}+\dfrac{2}{3}\right)\times2=\dfrac{23}{6}\)
Bài 1:
\(=\dfrac{-3-39}{42}+\dfrac{-6-11}{17}-\dfrac{1}{6}=-\dfrac{119}{48}\)
Bài 2:
=>x:5=-13/20
hay x=-65/20=-13/4
Bài 1:
3/4+5/4=8/4=2
2/3+3/4=8/12+9/12=17/12
1/3+5/7=7/21+15/21=22/21
Bài 2:
a: x-1/2=1/3
nên x=1/3+1/2=5/6
b: x-3/6=5/8
=>x-1/2=5/8
=>x=5/8+1/2=5/8+4/8=9/8
Bài 1:
\(=\dfrac{-3-39}{32}+\dfrac{-6-11}{17}+\dfrac{-1}{6}=-\dfrac{21}{16}+\dfrac{-1}{6}-1=-\dfrac{119}{48}\)
Bài 2:
\(\Leftrightarrow x:5=-\dfrac{13}{20}\)
hay x=-13/4
\(x^2+x=12\)
\(\Rightarrow x^2+x-12=0\)
\(\Rightarrow x\left(x-3\right)+4\left(x-3\right)=0\Rightarrow\left(x-3\right)\left(x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)
x/6 * 5/8 = 5/12
x/6 = 8/12
x = 8*6/12 = 4