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16 tháng 9 2016

(3x-14)^3=1000

3x-14=10

3x=24

x=8

vậy x=8

2 tháng 4 2022

1 ) \(lim_{x\rightarrow+\infty}\dfrac{3x^2+5}{x^3-x+2}=lim_{x\rightarrow+\infty}\dfrac{\dfrac{3}{x}+\dfrac{5}{x^3}}{1-\dfrac{1}{x^2}+\dfrac{2}{x^3}}=0\)

2 ) \(lim_{x\rightarrow-\infty}\dfrac{2x^2\left(3x^2-5\right)^3\left(1-x\right)^5}{3x^{14}+x^2-1}\)  \(=lim_{x\rightarrow-\infty}\dfrac{\dfrac{2}{x}\left(3-\dfrac{5}{x^2}\right)^3\left(\dfrac{1}{x}-1\right)^5}{3+\dfrac{1}{x^{12}}-\dfrac{1}{x^{14}}}=0\)

3 ) \(lim_{x\rightarrow+\infty}\dfrac{3x-\sqrt{2x^2+5}}{x^2-4}=lim_{x\rightarrow+\infty}\dfrac{\left(7x^2-5\right)}{\left(3x+\sqrt{2x^2+5}\right)\left(x^2-4\right)}\)

\(=lim_{x\rightarrow+\infty}\dfrac{\dfrac{7}{x}-\dfrac{5}{x^3}}{\left(3+\sqrt{2+\dfrac{5}{x^2}}\right)\left(1-\dfrac{4}{x^2}\right)}=0\)

23 tháng 2 2023

A) 3x² - x(3x - 5) = 9

3x² - 3x² + 5x = 9

5x = 9

x = 9/5

--------------------

B) 5x² + 9x - 2 = 0

5x² + 10x - x - 2 = 0

(5x² + 10x) - (x + 2) = 0

5x(x + 2) - (x + 2) = 0

(x + 2)(5x - 1) = 0

x + 2 = 0 hoặc 5x - 1 = 0

*) x + 2 = 0

x = -2

*) 5x - 1 = 0

5x = 1

x = 1/5

Vậy x = -2; x = 1/5

---------------------

D) 4(5 - 3x) = 5x - 5

20 - 12x = 5x - 5

-12x - 5x = -5 - 20

-17x = -25

x = 25/17

--------------------

E) 2x² - 11x + 14 = 0

2x² - 4x - 7x + 14 = 0

(2x² - 4x) - (7x - 14) = 0

2x(x - 2) - 7(x - 2) = 0

(x - 2)(2x - 7) = 0

x - 2 = 0 hoặc 2x - 7 = 0

*) x - 2 = 0

x = 2

*) 2x - 7 = 0

2x = 7

x = 7/2

Vậy x = 2; x = 7/2

23 tháng 2 2023

Câu C và F ghi đề bằng công thức đúng lại em

5 tháng 8 2020

chuyển đổi lại : (7x - 3) : 12 = 13

=> (7x - 3) = 13 * 12

=> 7x - 3 = 156

=> 7x = 159

=> x=  159/7

[(7x - 31) : 5] * 36 = 7236

=> [(7x - 31) : 5] = 7236 : 36 = 201

=> (7x - 31) : 5 = 201

=> 7x - 31 = 1005

=> 7x = 1036

=> x = 148

1 + 2 + 3 + 4 + 5 +... + 100 + x = 5350

SSH : \(\left(100-1\right):1+1=100\)

=> tổng : \(\frac{\left(1+100\right)\cdot100}{2}=5050\)

=> 5050 + x = 5350

=> x = 5350 - 5050 = 300

80 - 9(x - 4) = 35

=> 9(x - 4) = 80 - 35 = 45

=> x - 4 = 45 : 9

=> x - 4 = 5

=> x = 9

(3x - 21) : 4 + 108 = 114

=> (3x - 21) : 4 = 114 - 108 = 6

=> 3x - 21 = 24

=> 3x = 45

=> x = 15

[(6x - 72) : 2 - 84]*14 = 2814

=> [(6x - 72) : 2 - 84] = 201

=> (6x - 72) : 2 - 84 = 201

=> (6x - 72) : 2 = 285

=> 6x - 72 = 570

=> 6x = 642

=> x = 107

28x + 12x = 80

=> 40x = 80

=> x = 2

249 - 7(1 + x) = 200

=> 7(1 + x) = 49

=> 1 + x = 7

=> x = 6

20 - [(x - 5) * 7 + 4] = 2

=> [(x - 5) * 7 + 4] = 18

=> (x - 5)*7 + 4 = 18

=> (x - 5) * 7 = 14

=> x - 5 = 2

=> x = 7

\(\frac{7x-33}{12}=13\)

\(7x-33=13\cdot12\)

\(7x-33=156\)

\(7x=156+33\)

\(7x=189\)

\(x=\frac{189}{7}=27\)

\(\frac{7x-31}{5}\cdot36=7236\)

\(\frac{7x-31}{5}=\frac{7236}{36}\)

\(\frac{7x-31}{5}=201\)

\(7x-31=201\cdot5\)

\(7x-31=1005\)

\(7x=1005+31\)

\(7x=1036\)

\(x=\frac{1036}{7}=148\)

\(1+2+3+4+5+..+100+x=5350\)

\(\left(1+2+3+4+5+...+100\right)+x=5350\)

Phần 1 + 2 + 3 + 4 + 5 + ... + 100 có số số hạng là :

             \(\frac{100-1}{1}+1=100\) ( số hạng )

\(\Rightarrow\frac{\left(100+1\right)\cdot100}{2}+x=5350\)

\(5050+x=5350\)

\(x=5350-5050=300\)

\(80-9\left(x-4\right)=35\)

\(9\left(x-4\right)=80-35\)

\(9\left(x-4\right)=45\)

\(x-4=\frac{45}{9}\)

\(x-4=5\)

\(x=5+4=9\)

\(\frac{3x-21}{4}+108=114\)

\(\frac{3x-21}{4}=114-108\)

\(\frac{3x-21}{4}=6\)

\(3x-21=6\cdot4\)

\(3x-21=24\)

\(3x=24+21\)

\(3x=45\)

\(x=\frac{45}{3}=15\)

\(14\left(\frac{6x-72}{2}-84\right)=2814\)

\(3x-36-84=\frac{2814}{14}\)

\(3x-120=201\)

\(3x=201+120\)

\(3x=321\)

\(x=\frac{321}{3}=107\)

\(28x+12x=80\)

\(x\left(28+12\right)=80\)

\(x\cdot40=80\)

\(x=\frac{80}{40}=2\)

\(249-7\left(1+x\right)=200\)

\(-7\left(1+x\right)=200-249\)

\(-7\left(1+x\right)=-49\)

\(1+x=\frac{-49}{-7}\)

\(1+x=7\)

\(x=7-1=6\)

\(20-7\left(x-5\right)+4=2\)

\(20-7\left(x-5\right)=2-4\)

\(20-7\left(x-5\right)=-2\)

\(-7\left(x-5\right)=-2-20\)

\(-7\left(x-5\right)=-22\)

\(x-5=\frac{-22}{-7}\)

\(x=\frac{22}{7}+5=\frac{57}{7}\)

\(a,\left(7x-11\right)^3=2^5.5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=32.25+200\)

\(\Leftrightarrow\left(7x-11\right)^3=800+200\)

\(\Leftrightarrow\left(7x-11\right)^3=1000\)

\(\Leftrightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

\(b,3^2.x^2-2^2.x^2=5^5-\left(255:51\right).11\)

\(\Rightarrow x^2\left(3^2-2^2\right)=3125-5.11\)

\(\Rightarrow x^2\left(9-4\right)=3125-55\)

\(\Rightarrow5x^2=2970\)

\(\Rightarrow x^2=2970:5\)

\(\Rightarrow x^2=594\)

\(\Rightarrow x=3\sqrt{66}\)

13 tháng 6 2018

1/ (x+1)(-3)+5(x-4)=-3

\(\Leftrightarrow\)-3x - 3 + 5x - 20= -3

\(\Leftrightarrow\)2x - 23=-3

\(\Leftrightarrow\)x=10

2/3(5x-1) -x (x+1)+x2=14

\(\Leftrightarrow\)15x - 3 - x2 -x + x2=14

\(\Leftrightarrow\)14x=17

\(\Leftrightarrow\)x=17/14

3/2(x-1)-x(3-x)=x2

\(\Leftrightarrow\)2x - 2 - 3x + x2=x2

\(\Leftrightarrow\)2x-3x+x2-x2=2

\(\Leftrightarrow\)x= -2

4/ 3x(x+5)-2(x+5)=3x2

\(\Leftrightarrow\)3x2 + 15x - 2x - 10=3x2

\(\Leftrightarrow\)13x = 10

\(\Leftrightarrow\)x=10/13

5/ 4x(x+2)+x(4-x)=3x2+12

\(\Leftrightarrow\)4x2 + 8x + 4x - x2 = 3x2 + 12

\(\Leftrightarrow\)12x=12

\(\Leftrightarrow\)x=1