\(\frac{4^9.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
help Nhi nhaaaaaaaaaaaaaa! thanks .
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AM
27 tháng 6 2015
\(\frac{8^4.3^{12}-6^{11}}{4^9.9^5+6^9.120}=\frac{2^{12}.3^{12}-2^{11}.3^{11}}{2^{18}.3^{10}+3^9.2^9.2^3.3.5}=\frac{2^{11}.3^{11}\left(2.3-1\right)}{2^{18}.3^{10}+2^{12}.3^{10}.5}=\frac{2^{11}.3^{11}.5}{2^{12}.3^{10}.\left(2^6+5\right)}=\frac{2^{11}.3^{11}.5}{2^{12}.3^{10}.69}=\frac{3.5}{2.69}=\frac{5}{46}\)
NG
2
MA
28 tháng 8 2016
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2^{12}.3^{10}+3^{10}.2^{12}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}.6}{6^{12}-6^{11}}=\frac{2^{12}.3^{10}.6}{6^{11}\left(6-1\right)}=\frac{2^{10}.3^{10}\left(2^2+1\right).6}{6^{11}.5}=\frac{6^{11}.5}{6^{11}.5}=1\)
NH
0
NT
1
7 tháng 8 2016
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}.10=\frac{2^{12}.3^{10}+2^9.3^9.120}{2^{12}.3^{12}-2^{11}.3^{11}}.10=\frac{2^{10}.3^{10}\left(2^2+20\right)}{2^{10}.3^{10}\left(6^2-6\right)}.10=\frac{24.10}{30}=8\)
HQ
1
26 tháng 2 2022
\(=-\dfrac{2^{12}\cdot3^{10}+3^9\cdot2^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}+2^{11}\cdot3^{11}}\)
\(=-\dfrac{2^{12}\cdot3^{10}+3^{10}\cdot2^{12}\cdot5}{2^{11}\cdot3^{11}\cdot7}\)
\(=-\dfrac{3^{10}\cdot2^{12}\cdot6}{2^{11}\cdot3^{11}\cdot7}=-\dfrac{2}{3}\cdot\dfrac{6}{7}=\dfrac{-12}{21}=-\dfrac{4}{7}\)
19 tháng 10 2018
\(=\frac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot5\cdot3}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=\frac{2^{12}\cdot3^{10}\left(1+5\right)}{2^{11}\cdot3^{11}\left(2\cdot3-1\right)}\)\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{4}{5}\)
NV
19 tháng 10 2018
\(B=\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(B=\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(B=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(B=\frac{2^{11}.3^{10}.\left(2+2.5\right)}{2^{11}.3^{10}.\left(2.3^2-3\right)}\)
\(B=\frac{2+2.5}{2.3^2-3}\)
\(B=\frac{4}{5}\)
HL
1
\(\frac{4^9\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}=\frac{2^{18}\cdot3^{10}+2^9\cdot3^8\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\frac{2^{18}\cdot3^{10}+2^{12}\cdot3^9\cdot5}{2^{11}\cdot3^{11}\cdot5}=\frac{2^{12}\cdot3^9\left(2^6\cdot3+5\right)}{2^{11}\cdot3^{11}\cdot5}\)
\(=\frac{2\cdot\left(2^6\cdot3+5\right)}{3^2\cdot5}=\frac{394}{45}\)