56/63 x (9/16 + 27/24)
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IL
3
21 tháng 4 2018
Ta có :
\(\frac{x-1}{27}+\frac{x-2}{26}+\frac{x-3}{25}+\frac{x-4}{24}=4\)
\(\Leftrightarrow\)\(\left(\frac{x-1}{27}-1\right)+\left(\frac{x-2}{26}-1\right)+\left(\frac{x-3}{25}-1\right)+\left(\frac{x-4}{24}-1\right)=4-4\) ( trừ 2 vế cho 4 )
\(\Leftrightarrow\)\(\frac{x-28}{27}+\frac{x-28}{26}+\frac{x-28}{25}+\frac{x-28}{24}=0\)
\(\Leftrightarrow\)\(\left(x-28\right)\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}\right)=0\)
Vì \(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}\ne0\)
Nên \(x-28=0\)
\(\Rightarrow\)\(x=28\)
Vậy \(x=28\)
Chúc bạn học tốt ~
PL
21 tháng 4 2018
\(x-\frac{1}{27}+x-\frac{2}{26}+x-\frac{3}{25}+x-\frac{4}{24}=4\)
\(\left(x+x+x+x\right)-\left(\frac{1}{27}+\frac{2}{26}+\frac{3}{25}+\frac{4}{24}\right)=4\)
\(4x-\frac{7031}{17550}=4\)
\(4x=4+\frac{7031}{17550}\)
\(x=\frac{4+\frac{7031}{17550}}{4}=1+\frac{\frac{7031}{17550}}{4}\)
\(x=1+\frac{7031}{70200}\)
.........................................................................................
18 tháng 5 2020
Bài 1:
a) 19/27+9/7+6/27+5/7+2/7
= (19/27+6/27) + (9/7+5/7+2/7)
=1 + 16/7
=23/7
b) 2/7 + 27/48 + 7/16 +45/63
= (2/7 + 45/63) + (27/48 +7/16)
= (2/7 + 5/7) + ( 9/16 + 7/16)
= 1 + 1
=2
c) Tính bằng cách bình thường
Bài 2:
6/11 + x = 1
x = 1-6/11
x = 5/11
18 tháng 5 2020
Bài làm
a) \(\frac{19}{27}+\frac{9}{7}+\frac{6}{27}+\frac{5}{7}+\frac{2}{7}\)
\(=\frac{27}{27}+\frac{16}{7}\)
\(=1+\frac{16}{7}\)
\(=\frac{7}{7}+\frac{16}{7}\)
\(=\frac{23}{7}\)
b) \(\frac{2}{7}+\frac{27}{48}+\frac{7}{16}+\frac{45}{63}\)
\(=\left(\frac{18}{63}+\frac{45}{63}\right)+\left(\frac{27}{48}+\frac{21}{48}\right)\)
\(=\frac{63}{63}+\frac{48}{48}\)
\(=1+1\)
\(=2\)
c) \(\frac{17}{23}+\left(\frac{4}{7}-\frac{6}{13}\right)\)
\(=\frac{17}{23}+\left(\frac{52}{91}-\frac{42}{91}\right)\)
\(=\frac{17}{23}+\frac{10}{91}\)
\(=\frac{1547}{2093}+\frac{230}{2093}\)
\(=\frac{1770}{2093}\)
Bài 2
\(\frac{6}{11}+x=1\)
\(x=1-\frac{6}{11}\)
\(x=\frac{11}{11}-\frac{6}{11}=\frac{5}{11}\)
Vậy \(x=\frac{5}{11}\)
B
2 tháng 4 2019
1)
a)
\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)
\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)
\(\frac{-20}{5}< x< \frac{-3}{10}\)
\(\frac{-40}{10}< x< \frac{-3}{10}\)
\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)
VM
0
FS
6 tháng 3 2019
a) \(-\frac{1}{15}-\frac{1}{16}=-\frac{16}{240}-\frac{15}{240}=-\frac{31}{240}\)
b) \(\frac{7}{24}-\left(-\frac{5}{36}\right)=\frac{7}{24}+\frac{5}{36}=\frac{21}{72}+\frac{10}{72}=\frac{31}{72}\)
c) \(-\frac{7}{9}-\left(-\frac{7}{12}\right)=-\frac{7}{9}+\frac{7}{12}=-\frac{28}{36}+\frac{21}{36}=-\frac{7}{36}\)
6 tháng 3 2019
\(a)\frac{-1}{15}-\frac{1}{16}\)
\(\frac{-1}{15}-\frac{1}{16}.MSC:240\)
\(=\frac{-1.16}{15.16}-\frac{1.15}{16.15}=\frac{-16}{240}-\frac{15}{240}=\frac{-16-15}{240}=\frac{-31}{240}\)
\(b)\frac{7}{24}-\frac{-5}{36}\)
\(\frac{7}{24}-\frac{-5}{36}.MSC:72\)
\(=\frac{7.3}{24.3}-\frac{-5.2}{36.2}=\frac{21}{72}-\frac{-10}{72}=\frac{21-\left(-10\right)}{72}=\frac{31}{72}\)
\(c)\frac{-7}{9}-\frac{-7}{12}\)
\(\frac{-7}{9}-\frac{-7}{12}.MSC:36\)
\(=\frac{-7.4}{9.4}-\frac{-7.3}{12.3}=\frac{-28}{36}-\frac{-21}{36}=\frac{-28-\left(-21\right)}{36}=\frac{-7}{36}\)
Chúc bạn một ngày vui vẻ ~! ❤‿❤
Nếu có gì sai thì báo lỗi cho mình biết nhé.
5 tháng 3 2018
\(A=\frac{1\cdot2+2\cdot4+3\cdot6+4\cdot8+5\cdot10+6\cdot12}{3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20+18\cdot24}\)
\(A=\frac{2\cdot3\left[1\cdot2\right]+2\cdot3\left[2\cdot4\right]+2\cdot3\left[3\cdot6\right]+2\cdot3\left[4\cdot8\right]+2\cdot3\left[5\cdot10\right]}{3\cdot4\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}\)
\(A=\frac{\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}{2\cdot3\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}=\frac{1}{2\cdot3}=\frac{1}{6}\)
\(\dfrac{3}{2}\)
\(=\dfrac{56}{63}\times\dfrac{27}{16}=\dfrac{3}{2}\)