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19 tháng 3 2022

I'm hungry because I( have) ……didn't have………….. breakfast or lunch.

I'd rather you (do) …………did……..  the test well.

I distinctly remember (pay) ………paying……….. him. I gave him two dollars

Radio waves (discover) ……were discovered………….. by Heinrich Hertz 

Before she ( watch) ……watched…………..  TV, she (do) ……had done………….. homework

Four weeks  (be) ………is………..  a long time to wait for you.

The director as well as his staff  (have) ……has………….. to learn English.

We (listen) ………were listening……….. to the radio when it suddenly stopped working.

26 tháng 3 2023

5A

1B

3C

4D

\(#TyHM\)

30 tháng 11 2021

1 do you do

2 had done - went

3 went - had read

4 will attend

5 hadn't worn

6 to be

7 weren't sleeping - were playing

8 to be

9 had lived - moved

10 locking

11 had work - retired 

12 told - had learned

13 won't call

14 had met

30 tháng 11 2021

do you do

had done-went

went- had read

will attend

hadn't worn

to be

 

 

22 tháng 8 2023

12.2 cắt quá bạn đăng lại nhé

13

\(n_{Al}=\dfrac{10,8}{27}=0,4\left(mol\right)\)

a.

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

0,4->1,2----->0,4-------->0,6

\(V_{H_2}=0,6.22,4=13,44\left(l\right)\)

b. \(C\%_{HCl}=\dfrac{1,2.36,5.\left(100+20\right)\%}{200}=26,28\%\)

c. \(n_{HCl.dư}=(\dfrac{200.26,28\%}{100\%}:36,5)-1,2=0,24\left(mol\right)\)

\(C\%_{HCl.dư}=\dfrac{0,24.36,5.100\%}{10,8+200-0,6.2}=4,18\%\)

\(C\%_{AlCl_3}=\dfrac{0,4.133,5.100\%}{10,8+200-0,6.2}=25,48\%\)

22 tháng 8 2023

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25 tháng 12 2021

a: Xét tứ giác AEHF có 

\(\widehat{AEH}=\widehat{AFH}=\widehat{FAE}=90^0\)

Do đó: AEHF là hình chữ nhật

27 tháng 11 2021

1 were - would you play

2 weren't studying - would have 

3 had taken - wouldn't have got

4 would you go - could

5 will you give - is

6 recycle - won't be

7 had heard - wouldn't have gone

8 would you buy - had

9 don't hurry - will miss

10 had phoned - would have given

11 were - wouldn't eat

12 will go - rains

13 had known - would have sent

14 won't feel - swims

15 hadn't freezed - would have gone

b) Áp dụng hệ thức lượng trong tam giác vuông vào ΔAHB vuông tại H có HM là đường cao ứng với cạnh huyền AB, ta được:

\(AM\cdot AB=AH^2\)(1)

Áp dụng hệ thức lượng trong tam giác vuông vào ΔAHC vuông tại H có HN là đường cao ứng với cạnh huyền AC, ta được:

\(AN\cdot AC=AH^2\)(2)

Từ (1) và (2) suy ra \(AM\cdot AB=AN\cdot AC\)

14 tháng 12 2018

\(\left(2119-x\right)\cdot2,23=174\)

\(\Rightarrow219-x=\frac{174}{2,23}\)

\(x=219-\frac{174}{2,23}\)