Question

[Nguyễn Thanh Lâm]

Ai giải chi tiết hộ mình với sắp thi rồi :((

Answer 1

[Nguyễn Hoàng Minh]

$a\big)$

$ZnO+H_2\xrightarrow{t^o}Zn+H_2O$

$CuO+H_2\xrightarrow{t^o}Cu+H_2O$

$b\big)$

$n_{H_2}=\frac{3,92}{22,4}=0,175(2)$

Theo PT: $n_{H_2O}=n_{H_2}=0,175(mol)$

$\to y=m_{H_2O}=0,175.18=3,15(g)$

BTKL:

$m_M+m_{H_2}=m_N+m_{H_2O}$

$\to m_N=14,1+0,175.2-3,15=11,3(g)$

$\to x=11,3(g)$