2227\17
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Theo bài ra , ta có :
\(151-2\left(x-6\right)=2227:17\)
\(\Leftrightarrow151-2\left(x-6\right)=131\)
\(\Leftrightarrow2\left(x-6\right)=20\)
\(\Leftrightarrow x-6=10\)
\(\Leftrightarrow x=16\)
Vậy \(x=16\)
151 - 2(x-6) = 2227 :17 = 131
2(x-6) = 151 - 131=20
x - 6 = 20 : 2=10
x = 10+6 =16
151-2.(x-6)=2227:17
151-2.(x-6)=131
2.(x-6)=151 - 131
2.(x-6)=20
x-6=20:2
x-6=10
x=10+6
x=16
155 - 2.(x - 6) = \(\frac{2227}{17}\)
2.(x - 6) = 155 - \(\frac{2227}{17}\)
x - 6 = 24 : 2
x = 12 + 6
x = 18
\(151-2\cdot\left(x-6\right)=2227:17\)
\(151-2\left(x-6\right)=131\)
\(2\left(x-6\right)=151-131\)
\(2\left(x-6\right)=20\)
\(x-6=20:2\)
\(x-6=10\)
\(x=10+6\)
\(x=16\)
\(151-2\times\left[x-6\right]=2227:17\)
\(151-2\times\left[x-6\right]=131\)
\(2\times\left[x-6\right]=151-131\)
\(2\times\left[x-6\right]=20\)
\(x-6=20:2\)
\(x-6=10\)
\(x=10+6\)
\(x=16\)
151-2x[x-6]=131
2x[x-6]=151-131
2x[x-6]=20
x-6=20:2
x-6=10
x=10+6
x=16
a)
151 - 2 x ( x-6 ) = 2227 : 17
2 x ( x-6 ) = 131
2 x ( x-6 ) = 151 - 131
2 x ( x-6 ) = 20
x-6 = 20 : 2
x - 6 = 10
x = 10 + 6
x = 16
b)
\(\dfrac{2}{3}-\dfrac{1}{4}=\dfrac{5}{12}\\ X=\dfrac{5}{12}:\dfrac{1}{3}=\dfrac{5}{4}\)
a) \(x-1\frac{4}{5}=\frac{10}{5}\)
\(\Rightarrow x=2+1\frac{4}{5}=3\frac{4}{5}=\frac{19}{5}\)
b) \(5,85:x=26-25,5\)
\(\Leftrightarrow5,85:x=0,5\)
\(\Rightarrow x=5,85:0,5=11,7\)
c) \(151-\left(-2\right).\left(x-6\right)=2227:17=131\)
\(\Rightarrow\left(-2\right).\left(x-6\right)=151-131=20\)
\(\Rightarrow\left(x-6\right)=20:\left(-2\right)=-10\)
\(\Rightarrow x=-4\)
d) \(\frac{2}{3}-\frac{1}{3}x=\frac{1}{4}\)
\(\Rightarrow \frac{1}{3}x=\frac{2}{3}-\frac{1}{4}=\frac{5}{12}\)
\(\Rightarrow x=\frac{5}{12}:\frac{1}{3}=\frac{5}{4}\)
dấu chấm (.) là dấu nhân nhé
\(\Leftrightarrow\left(\dfrac{2107-x}{9}-10\right)+\left(\dfrac{2177-x}{8}-20\right)+\left(\dfrac{2227-x}{7}-30\right)+\left(\dfrac{2257-x}{6}-40\right)=0\)
=>2017-x=0
=>x=2017
= 131
tích mk bn sẽ lun gặp may mắn !!
131 k nha