Thực hiện phép tính sau:
M= 9/40- 11/60+ 13/84 - 15/112
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Ta có: \(M=\dfrac{9}{40}-\dfrac{11}{60}+\dfrac{13}{84}-\dfrac{15}{112}\)
\(=\dfrac{378}{1680}-\dfrac{308}{1680}+\dfrac{260}{1680}-\dfrac{225}{1680}\)
\(=\dfrac{105}{1680}=\dfrac{1}{16}\)
M=9/40-11/60+13/84-15/112
M=27/120-22/120+52/336-45/336
M=1/24+1/48
M=2/48+1/48=3/48=1/16
\(M=\dfrac{9}{40}-\dfrac{11}{60}+\dfrac{13}{84}-\dfrac{15}{112}\)
\(M=\left(\dfrac{90}{40}-\dfrac{11}{60}\right)+\left(\dfrac{13}{84}-\dfrac{15}{112}\right)\)
\(M=\dfrac{27}{120}-\dfrac{22}{120}+\dfrac{52}{336}-\dfrac{45}{336}\)
\(M=\dfrac{5}{120}+\dfrac{7}{336}\)
\(M=\dfrac{1}{24}+\dfrac{1}{48}\)
\(M=\dfrac{3}{48}=\dfrac{1}{16}\)
M=\(\dfrac{9}{40}-\dfrac{11}{60}+\dfrac{13}{84}-\dfrac{15}{112}\)
M=\(\dfrac{1}{24}+\dfrac{13}{84}-\dfrac{15}{112}\)
M=\(\dfrac{11}{56}-\dfrac{15}{112}\)
M=\(\dfrac{1}{16}\)
M= 9/40-11/60+13/84-15/112
M=378/1680-308/1680+260/1680-225/1680
M=\(\frac{378-308+260-225}{1680}\)
M=\(\frac{105}{1680}\)
M= \(\frac{1}{16}\)
M= \(\dfrac{9}{40}-\dfrac{11}{60}+\dfrac{13}{84}-\dfrac{15}{112}\)
= (\(\dfrac{9}{40}-\dfrac{11}{60}\)) + (\(\dfrac{13}{84}-\dfrac{15}{112}\))
= (\(\dfrac{27}{120}-\dfrac{22}{120}\)) + (\(\dfrac{52}{336}-\dfrac{45}{336}\))
= \(\dfrac{1}{24}+\dfrac{1}{48}\)
= \(\dfrac{2}{48}+\dfrac{1}{48}\)
=\(\dfrac{3}{48}=\dfrac{1}{16}\)