Tính hợp lý
a) \(5^6.4^3.19\)
b) \(123.25^4.16^2\)
c) \(73.5^{12}.8^4\)
d) \(1111.8^4.25^7\)
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Câu 5:
a: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
\(=31\left(-18-81-1\right)\)
\(=31\cdot\left(-100\right)=-3100\)
b: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)
\(=\left(-12\right)\left(47+52+1\right)\)
\(=-12\cdot100=-1200\)
c: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)
\(=13\cdot45-3\cdot45\)
\(=45\cdot10=450\)
d: \(-48+48\left(-78\right)+48\left(-21\right)\)
\(=48\left(-1-78-21\right)\)
\(=48\left(-100\right)=-4800\)
Câu 4:
a: \(\left(-6-2\right)\left(-6+2\right)=\left(-8\right)\cdot\left(-4\right)=32\)
b: \(\dfrac{\left(7\cdot3-3\right)}{-6}=\dfrac{21-3}{-6}=\dfrac{18}{-6}=-3\)
c: \(\left(-5+9\right)\cdot\left(-4\right)=4\cdot\left(-4\right)=-16\)
d: \(\dfrac{72}{-6\cdot2+4}=\dfrac{72}{-12+4}=\dfrac{72}{-8}=-9\)
Câu 2:
a: x-158=32
=>x=158+32
=>x=190
b: \(x\cdot24=264\)
=>\(x=\dfrac{264}{24}\)
=>x=11
c: \(6x+9=3^7:3^4\)
=>\(6x+9=3^3\)
=>6x+9=27
=>6x=18
=>x=18/6=3
Câu 1:
a: \(86\cdot19+14\cdot19\)
\(=19\left(86+14\right)\)
\(=19\cdot100=1900\)
b: \(4\cdot\left(-5\right)^2-104\cdot\left(-5\right)^2\)
\(=4\cdot25-104\cdot25\)
\(=25\left(4-104\right)=-100\cdot25=-2500\)
c: \(7\cdot\left(-2\right)\cdot8\left(-5\right)\)
\(=7\cdot2\cdot8\cdot5\)
\(=56\cdot10=560\)
d: \(59-\left[59+\left(-76\right)\right]\)
\(=59-59+76\)
=76
a: \(=\dfrac{48-45}{54}\cdot\dfrac{9}{4}=\dfrac{3}{54}\cdot\dfrac{9}{4}=\dfrac{27}{216}=\dfrac{1}{8}\)
b: \(=\dfrac{6}{5}+1=\dfrac{11}{5}\)
c: \(=\dfrac{7\cdot28\cdot15}{9\cdot25\cdot14}=\dfrac{1}{2}\cdot\dfrac{28}{25}\cdot\dfrac{5}{3}=\dfrac{140}{150}=\dfrac{14}{15}\)
a: \(=\dfrac{2^5\cdot3^5\cdot2^{12}\cdot2^{16}\cdot5^{16}}{2^{30}\cdot3^{10}\cdot5^{16}}=\dfrac{2^{33}\cdot3^5}{2^{30}\cdot3^{10}}=\dfrac{8}{243}\)
c: \(=\dfrac{4^7\cdot3^{12}\cdot5^4+3^{12}\cdot5^6\cdot4^7}{2^{14}\cdot3^{14}\cdot5^4+2^{14}\cdot3^{14}\cdot5^6}\)
\(=\dfrac{2^{14}\cdot3^{12}\cdot5^4\left(1+25\right)}{2^{14}\cdot3^{14}\cdot5^4\left(1+25\right)}=\dfrac{1}{9}\)
a: =3/4-19/18-3/4
=-19/18
b: =24-24x47-24x54
=24(1-47-54)
=24x(-100)=-2400
Bài 5:
a: x(x-4)=0
=>\(\left[{}\begin{matrix}x=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)
b: Đề thiếu vế phải rồi bạn
Bài 6:
a: \(\left(-5\right)\cdot\left(-6\right)\cdot\left(-4\right)\cdot2\)
\(=-\left(2\cdot5\right)\cdot\left(4\cdot6\right)\)
\(=-24\cdot10=-240\)
b: \(\left(-3\right)\cdot2\cdot\left(-8\right)\cdot5\)
\(=3\cdot2\cdot8\cdot5\)
\(=\left(3\cdot8\right)\cdot\left(2\cdot5\right)\)
\(=24\cdot10=240\)
a) \(5^6.4^3.19=5^6.\left(2^2\right)^3.19=\left(5.2\right)^6.19=1000000.19=19000000\)
b)\(123.25^4.16^2=123.5^8.2^8=123.\left(5.2\right)^8=123.10^8=123.100000000=12300000000\)
c) \(73.5^{12}.8^4=73.5^{12}.\left(2^3\right)^4=73.\left(5.2\right)^{12}=73.10^{12}=73.1000000000000=73000000000000\)
d)\(1111.8^4.25^7=1111.\left(2^3\right)^4.\left(5^2\right)^7=1111.2^{12}.5^{14}=\left(1111.25\right).\left(2.5\right)^{12}=27775.10^{12}\)
\(=27775.1000000000000=27775000000000000\)
a)56x43=1000000
1000000x19=19000000
b) 12300000000
c) 73000000000000
d) Ko ra đc