(9\(\frac{30303}{80808}\)+ 7\(\frac{303030}{484848}\)) + 4,03
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(H=\left(9+\dfrac{3}{8}+7+\dfrac{5}{8}\right)+4.03=17+4.03=21.03\)
![](https://rs.olm.vn/images/avt/0.png?1311)
H = (9/30303/80808+7/303030/484848)+4,03
= ( \(\frac{75}{8}+\frac{61}{8}\)) + \(\frac{403}{100}\)
= \(\frac{136}{8}\)+ \(\frac{403}{100}\)
= 17 + \(\frac{403}{100}\)
= \(\frac{2103}{100}\)
Vậy : H = \(\frac{2103}{100}\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(C=9\frac{30303}{80808}+4,03+7\frac{303030}{484848}\)
\(=9\frac{3}{8}+4\frac{3}{100}+7\frac{5}{8}\)
\(=\left(9+7\right)+\left(\frac{3}{8}+\frac{5}{8}\right)+4\frac{3}{100}\)
\(=16+1+4\frac{3}{100}\)
\(=21\frac{3}{100}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
I=10101(5/111111+5/222222+4/3.7.11.13.37)
I=10101(5/111111+5/222222+4/111111)
I=10101(10/222222+5/222222+8/222222)
I=10101.23/222222
I=232323/222222
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\left(9+\frac{30303}{80808}+7+\frac{303030}{484848}\right)+4,03\)
\(A=\left(9+\frac{3\times10101}{8\times10101}+7+\frac{30\times10101}{48\times10101}\right)+4,03\)
\(A=\left(9+\frac{3}{8}+7+\frac{5}{8}\right)+4,03\)
\(A=\left(9+7+\frac{3}{8}+\frac{5}{8}\right)+4,03\)
\(A=\left(16+1\right)+4,03\)
\(A=17+4,03=21,03\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(F=\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}\left(21\frac{3}{7}+18\frac{4}{7}\right)\right).\frac{15}{78}=\left(\frac{39}{4}.40\right).\frac{15}{78}=390.\frac{15}{78}=75\)\(H=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03=\left(9\frac{3}{8}+7\frac{30}{48}\right)+4,03=17+4,03=21,03\)