Ai giúp mk câu này vs
\(3^{x-1}:3=\frac{1}{243}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, \(\frac{6^2+3.6^2+3^2}{-13}=\frac{6^2\left(3+1\right)+3^2}{-13}=\frac{144+9}{-13}=\frac{-153}{13}\)
b, \(\frac{81}{\left(-3\right)}=\frac{-243}{x}\)
< Chắc ý bạn là như vậy nhỉ >
=> x = [ ( -243 ) . ( -3 ) ] : 81
=> x = 9
\(a,\frac{6^3+3.6^2+3^3}{-13}=\frac{2^3.3^3+3.3^2.2^2+3^3}{-13}=\frac{2^3.3^3+3^3.2^2+3^3}{-13}\)
\(=\frac{3^3.\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=-3^3=-27\)
\(\frac{1}{3}\) + \(\frac{5}{6}\): \(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)
<=> \(\frac{5}{6}\):\(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)- \(\frac{1}{3}\)
<=> \(\frac{5}{6}\) : \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{12}\)
<=> \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{6}\) : \(\frac{5}{12}\)
,<=> \(\left(x-2\frac{1}{5}\right)\)= 2
<=. x = 2 + \(\frac{11}{5}\)
<=> x = \(\frac{21}{5}\)
a)\(\frac{x+3}{x+5}=7\Leftrightarrow x+3=7\left(x+5\right)\)
\(\Leftrightarrow x+3=7x+35\)
\(\Leftrightarrow-6x=32\)
\(\Leftrightarrow x=-\frac{16}{3}\)
b)\(\frac{2x-1}{3x+5}=-\frac{2}{3}\)
\(\Leftrightarrow3\left(2x-1\right)=-2\left(3x+5\right)\)
\(\Leftrightarrow6x-3=-6x-10\)
\(\Leftrightarrow12x=-7\)
\(\Leftrightarrow x=-\frac{7}{12}\)
c)\(\frac{x+1}{4}=\frac{9}{x+1}\Leftrightarrow\left(x+1\right)^2=36\)
\(\Leftrightarrow\left(x+1\right)^2=6^2\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=6\\x+1=-6\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\x=-7\end{cases}}}\)
d)\(\frac{6x-1}{2x+3}=\frac{3x}{x+2}\)
\(\Leftrightarrow\left(6x-1\right)\left(x+2\right)=3x\left(2x+3\right)\)
\(\Leftrightarrow6x^2+12x-x-2=6x^2+9x\)
\(\Leftrightarrow2x=2\Leftrightarrow x=1\)
X-1/4.x=6/11.(6/12+9/12+-4/12)
X-1/4.x=6/11.11/12
X-1/4.x=1/2
X.(1-1/4)=1/2
X.(4/4+-1/4)=1/2
X.3/4=1/2
X=1/2:3/4
X=1/2.4/3
X=2/3
Giai thich trong mot bai toan neu co hai dau x ta se ko tinh duoc trong bai toan nay x-25℅.x=6/11.(1/2+3/4+1/3) co hai dau x nen ta phai dua x ra ngoai lam h chung x dung mot minh se la x.1 khi ta bo x ra ngoai thi ben trong con 1-25℅ roi ta tinh ra sau do lam binh thuong
a) (x + 1/2)^2 = 1/16
=> (x + 1/2)^2 = (1/4)^2 hoặc (x + 1/2)^2 = (-1/4)^2
=> x + 1/2 = 1/4 hoặc x + 1/2 = -1/4
* x + 1/2 = 1/4
x = 1/4 - 1/2
x = -1/4
* x + 1/2 = -1/4
x = -1/4 - 1/2
x = -3/4
Vậy x = -1/4 hoặc x = -3/4
b) 2^x+2 - 2^x = 9^6
=> 2^x . 2^2 - 2^x = 9^6
=> 2^x . (2^2 - 1) = 9^6
=> 2^x . (4 - 1) = 9^6
=> 2^x . 3 = (3^2)^6
=> 2^x . 3 = 3^12
=> 2^x = 3^12 : 3
=> 2^x = 3^11
Vì 3^11 không chia hết cho 2
=> Không có giá trị nào của x thõa mãn đề bài
c) (3^x)^2 : 3^3 = 1/243
=> 3^2x = 1/243 . 3^3
=> 3^2x = 1/243 . 27
=> 3^2x = 1/9
=> 3^2x . 9 = 1
=> 3^2x . 3^2 = 1
=> 3^2x+2 = 1
=> 3^2x+2 = 3^0
=> 2x + 2 = 0
=> 2x = 0 - 2
=> 2x = -2
=> x = -2 : 2
=> x = -1
a\(\left(x+\frac{1}{2}\right)^2=\left(\frac{1}{4}\right)^2
\)
\(\Rightarrow x+\frac{1}{2}=\frac{1}{4}\)
\(\Leftrightarrow x=\frac{1}{4}-\frac{1}{2}\)
\(\Rightarrow x=\frac{-1}{4}\)
12x+3.23=23.x-4.32
12x+3.8=8.x-4.9
12x+24=8x-36
12x-8x=36-24
4x=12
x=12:4=3
\(\Rightarrow3^{x-1}=\frac{1}{243}x3\)
\(\Rightarrow3^{x-1}=\frac{1}{81}\)
Ko có x thỏa mãn
\(3^{x-1}:3=\frac{1}{243}\)
\(3^{x-2}=3^{-5}\)
\(\Rightarrow x-2=-5\)
\(x=-3\)
Vậy x= -3