a, 3/10 + 5/8 =
b, 1/8 + 5/6 =
c, 1/3 + 1/6 + 1/18 =
GIÚP EM GIẢI CHI TIẾT VỚI Ạ:3
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a: =-5/9-4/9+8/15+7/15-2/11=-2/11
b: =10/17+7/17-5/13-8/13+11/25
=11/25
c: =(9/12-2/12)*3/2=7/12*3/2=21/24=7/8
d: =(31/10-25/10)*3-2
=3/5*3-2
=9/5-2
=-1/5
a) \(\dfrac{3}{8}+\dfrac{15}{-25}+\dfrac{3}{5}\)
\(=\dfrac{-9}{40}+\dfrac{3}{5}\)
\(=\dfrac{3}{8}\)
b) \(\dfrac{-5}{18}+\dfrac{23}{45}-\dfrac{9}{10}\)
\(=\dfrac{7}{30}-\dfrac{9}{10}\)
\(=\dfrac{-2}{3}\)
c) \(\dfrac{-5}{12}+\dfrac{15}{18}-2,25\)
\(=\dfrac{5}{12}-2,25\)
\(=\dfrac{-11}{6}\)
d) \(\dfrac{5}{6}+\dfrac{2}{3}-0,5\)
\(=\dfrac{3}{2}-0,5\)
\(=1\)
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
a) 2/5 < x < 6/5
=> x = 1 ( =5/5 ) (vì x thuộc Z)
Vậy x = 1
b) 3/5 < 3/x < 3/2
=> 5 > x > 2
=> x thuộc { 4 ; 3 } (vì x thuộc Z)
Vậy ...
c) 3/8 + -11/8 < x < 22/9 + 5/18
=> -8/8 < x < 49/18
=>-1 < x < 2+13/18
=> x thuộc {0; 1; 2} ( vì x thuộc Z )
Vậy...
a) -1+2-3+4-5+6-....-2015+2016-2017+2018
= (-1+2)+(-3+4)+(-5+6)+.….+(-2015+2016)+(-2017+2018)
= 1+1+1+....+1+1
( Có tất cả 1009 số 1)
= 1009
b)1-2+3-4+5-6+.….+1245-1246+1247-1248
=(1-2)+(3-4)+(5-6)+....+(1245-1246)+(1247-1248)
=-1+(-1)+(-1)+....+(-1)+(-1)
(Có tất cả 624 số (-1))
= -624
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17+18 = 171 nhé
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17+18. = 171
a: 3/5+1/2=6/10+5/10=11/10
b: 3/2+5/4+5/8=12/8+10/8+5/8=27/8
c: 1/6+4/5+5/2=5/30+24/30+75/30=104/30=52/15
a \(\dfrac{11}{10}\)
b \(\dfrac{27}{8}\)
c \(\dfrac{52}{15}\)
a) \(\left(\frac{-1}{2}\right)+\left|\frac{-7}{6}\right|+\left(\frac{-7}{8}\right)=\frac{-1}{2}+\frac{7}{6}+\left(\frac{-7}{8}\right)=\frac{-5}{24}\)
b) \(\frac{3}{2}.\left|2+x\right|=\frac{5}{4}\)
\(\Rightarrow\left|2+x\right|=\frac{5}{4}:\frac{3}{2}=\frac{5}{6}\)
\(\Rightarrow2+x=\pm\frac{5}{6}\)
\(\Rightarrow\orbr{\begin{cases}2+x=\frac{5}{6}\Rightarrow x=\frac{5}{6}-2=\frac{-7}{6}\\2+x=\frac{-5}{6}\Rightarrow x=\frac{-5}{6}-2=\frac{-17}{6}\end{cases}}\)
Vậy \(x=\left\{\frac{-7}{6};\frac{-17}{6}\right\}\)
c) Ta có: \(\frac{3,7}{x}=\frac{-5}{1,2}\Rightarrow3,7.1,2:\left(-5\right)=x\)
\(\Rightarrow x=-0,888\)
d) Tự làm
A=(\(\frac{-1}{2}\))+|\(\frac{-7}{6}\)|+(\(\frac{-7}{8}\))
=(\(\frac{-1}{2}\))+\(\frac{-7}{6}\)+(\(\frac{-7}{8}\))
=\(\frac{2}{3}\)+(\(\frac{-7}{8}\))
=\(\frac{-5}{24}\)
Vậy x=\(\frac{-5}{24}\)
B=\(\frac{3}{2}\)x|2+x|=\(\frac{5}{4}\)
=|2+x|=\(\frac{5}{4}\):\(\frac{3}{2}\)
=\(\orbr{\begin{cases}2+x=\frac{5}{6}\\2+x=\frac{-5}{6}\end{cases}}\)
=\(\orbr{\begin{cases}x=\frac{5}{6}-2\\x=\frac{-5}{6}-2\end{cases}}\)
=\(\orbr{\begin{cases}x=-1\frac{1}{6}\\x=-2\frac{5}{6}\end{cases}}\)
Vậy x\(\in\){\(-1\frac{1}{6}\);\(-2\frac{5}{6}\)}
a, \(\frac{3}{10}+\frac{5}{8}=\frac{24}{80}+\frac{50}{80}=\frac{74}{80}=\frac{37}{40}\)
b, \(\frac{1}{8}+\frac{5}{6}=\frac{3}{24}+\frac{20}{24}=\frac{23}{24}\)
c, \(\frac{1}{3}+\frac{1}{6}+\frac{1}{8}=\frac{8}{24}+\frac{4}{24}+\frac{3}{24}=\frac{15}{24}=\frac{5}{8}\)
#Fox