a) (7x – 15).8 – 21 = 27
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(7x - 15).8 - 21 = 27
(7x - 15).8 = 27 + 21
(7x - 15).8 = 48
7x - 15 = 48:8
7x - 15 = 6
7x = 6 + 15
7x = 21
x = 21 : 7
x = 3
Vậy x = 3
(7x - 15).8 - 21 = 27
(7x - 15).8 = 27 + 21
(7x - 15).8 = 48
7x - 15 = 48:8
7x - 15 = 6
7x = 6 + 15
7x = 21
x = 21 : 7
x = 3
Vậy x = 3
câu 1
\(\frac{8}{7}x-\frac{10}{3}=-\frac{5}{21}\)
câu 2
x:27=-2:3,6
a: =1/8-1/8+2/5=2/5
b: =(-1/15-14/15)+(23/27+31/27)=2-1=1
c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)
d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)
1.
b) \(3^x+3^{x+2}=2430\)
\(\Rightarrow3^x.1+3^x.3^2=2430\)
\(\Rightarrow3^x.\left(1+3^2\right)=2430\)
\(\Rightarrow3^x.10=2430\)
\(\Rightarrow3^x=2430:10\)
\(\Rightarrow3^x=243\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\)
Vậy \(x=5.\)
c) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\Rightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=15\\2x-15=\pm1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=15:2\\2x-15=1\\2x-15=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{15}{2}\\2x=16\\2x=14\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{15}{2}\\x=8\\x=7\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{15}{2};8;7\right\}.\)
Chúc bạn học tốt!
\(\left(7x-15\right).8-21=27\\ \Rightarrow\left(7x-15\right).8=48\\ \Rightarrow7x-15=6\\ \Rightarrow7x=21\\ \Rightarrow x=3\)
a: =>(7x-15)x8=48
=>7x-15=6
=>7x=21
hay x=3