Question

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Answer 1

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`Answer:`

\(\text{lim }\frac{2.4^n+1}{1-4^{n+2}}\)

Chia cả tử và mẫu cho `4^n` được:

\(\text{lim }\frac{2.4^n+1}{1-4^{n+2}}\)

\(=\text{lim }\frac{\frac{2.4^n+1}{4^n}}{\frac{1-4^{n+2}}{4^n}}\)

\(=\text{lim }\frac{2+\frac{1}{4^n}}{\frac{1}{4^n}-4^2}\)

\(=\frac{2+0}{0-4^2}\)

\(=-\frac{1}{8}\)