2750-(2085+2750)-[-438-(29 -438)]=
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a-[171+(171+23)]-[172-(38+172)]-49
=[171+194]-[172-210]-49
=365-(-38)-49
=403-49=354
1) = 2750 - 1229 + 2570 + 438 + 29 + 438
= (2750 + 2750) - (1229 - 29) + (438 + 438)
= 5500 - 1200 + 876
= 5176
2) = 38.9 + 17.9 - 35.9 - 11.35
= (38+17-35).9 - 11.35
= 20.9 - 11.35
= 180 - 385
= -205
3) = 500 - \(\left\{5.\left[409-\left(24-21\right)^2\right]+1000\right\}\) : 15
= 500 - \(\left\{5.\left[409-9\right]+1000\right\}:15\)
= 500 - \(\left\{5.400+1000\right\}:15\)
= 500 - (2000 + 1000) : 15
= 500 - 200
= 300
- 482 - ( 176 - 482 ) - [ 2750 - ( 176 + 2750 ) ]
= - 482 - 176 + 482 - ( 2750 - 2926 )
= 482 - 482 - 176 - ( - 176 )
= 0 - 0
= 0
=438.(1/111.113+1/113.113+...+1/217.219)
=438.1/2.(2/111.113+2/113.115+...+1/217.219)
=438.1/2.(1/111-1/113+1/113-1/115+...+1/217-1/219)
=438.1/2.(1/111+0+0+..+0-1/219)
=438.1/2.(1/111-1/219)=219/111-1=
b tự tính
\(A=\frac{438}{111.113}+\frac{438}{113.115}+\frac{438}{115.117}+...+\frac{438}{217.219}\)
\(A=219\left(\frac{2}{111.113}+\frac{2}{113.115}+\frac{2}{115.117}+...+\frac{2}{217.219}\right)\)
\(A=219\left(\frac{1}{111}-\frac{1}{113}+\frac{1}{113}-\frac{1}{115}+\frac{1}{115}-\frac{1}{117}+...+\frac{1}{217}-\frac{1}{219}\right)\)
\(A=219\left(\frac{1}{111}-\frac{1}{219}\right)\)
Trả lời:
2750-(2085+2750)-[-438-(29 -438)]
= 2750-2085 -2750 -{-438-29+438}
=-2085+29=-2056
2750−(2085+2750)−[−438−(29−438)]2750-(2085+2750)-[-438-(29-438)]
=2750−(2085+2750)−[−438−29+438]=2750-(2085+2750)-[-438-29+438]
=2750−2085−2750−[−438−29+438]=2750-2085-2750-[-438-29+438]
=2750−2085−2750+438+29−438=2750-2085-2750+438+29-438
=(2750−2750)−2085−(438−438)+29=(2750-2750)-2085-(438-438)+29
=0−2085−0+29=0-2085-0+29
=−2056