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a, (\(\dfrac{9}{10}\) - \(\dfrac{15}{16}\)) \(\times\) ( \(\dfrac{5}{12}\) - \(\dfrac{11}{15}\) - \(\dfrac{7}{20}\))
= (\(\dfrac{72}{80}\) - \(\dfrac{75}{80}\)) \(\times\) (\(\)\(\dfrac{25}{60}\) - \(\dfrac{44}{60}\) - \(\dfrac{21}{60}\))
= - \(\dfrac{3}{80}\) \(\times\) (- \(\dfrac{2}{3}\))
= \(\dfrac{1}{40}\)
b, (-1)3 + (- \(\dfrac{2}{3}\))2 : 2\(\dfrac{2}{3}\) + \(\dfrac{5}{6}\)
= -13 + \(\dfrac{4}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{5}{6}\)
= -1 + \(\dfrac{4}{9}\) \(\times\) \(\dfrac{3}{8}\) + \(\dfrac{5}{6}\)
= -1 + \(\dfrac{1}{6}\) + \(\dfrac{5}{6}\)
= -1 + 1
= 0
Đặt tổng trên = A
\(A=\frac{15}{1.2}+\frac{15}{2.3}+\frac{15}{3.4}+...+\frac{15}{19.20}\)
\(A:15=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}\)
\(A:15=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}\)
\(A:15=1-\frac{1}{20}=\frac{19}{20}\)
\(A=\frac{19}{20}.15=\frac{57}{4}\)
\(A=\frac{15}{1.2}+\frac{15}{2.3}+\frac{15}{3.4}+...+\frac{15}{19.20}\)
\(A:15=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}\)
\(A:15=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}\)
\(A:15=1-\frac{1}{20}=\frac{19}{20}\)
\(A=\frac{19}{20}.15=\frac{57}{4}\)
a: =1/8-1/8+2/5=2/5
b: =(-1/15-14/15)+(23/27+31/27)=2-1=1
c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)
d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)
12 + 3 - 1 = 14 17 - 5 + 2 = 14 15 - 3 - 1 = 11
15 + 2 - 1 = 16 16 - 2 + 1 = 15 19 - 2 - 5 = 12
Tính nhẩm rồi điền kết quả vào chỗ trống.
14 - 1 = 13 15 - 4 = 11 17 - 2 = 15 15 - 3 = 12
15 - 1 = 14 19 - 8 = 11 16 - 2 = 14 15 - 2 = 13
7/15+18/15 = 25/15 = 5/3 5/4+17/12= 15/12 + 17/12 = 32/12 = 8/3 1/2+1/6+2/3 = 3/6 + 1/6 + 4/6 = 8/6 = 4/3 2+1/3 = 7/3
\(\dfrac{7}{15}+\dfrac{8}{15}=1\)
\(\dfrac{5}{4}+\dfrac{17}{12}=\dfrac{15}{12}+\dfrac{17}{12}=\dfrac{32}{12}=\dfrac{8}{3}\)
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{2}{3}=\dfrac{3}{6}+\dfrac{1}{6}+\dfrac{4}{6}=\dfrac{8}{6}=\dfrac{4}{3}\)
\(2+\dfrac{1}{3}=\dfrac{6}{3}+\dfrac{1}{3}=\dfrac{7}{3}\)
1+2+3+...+15=1+2+3+4+5+6+7+8+9+10+11+12+13+14+15
Trước tiên ta pải tìm xem dãy số này có bao nhiêu chữ số \(\frac{15-1}{1}+1=15\)( số)
Ta có : 1+2+3+...+15=\(\frac{\left(15+1\right)\times15}{2}=240:2=120\)
Vậy: 1+2+3+...+15=120