Tìm x :
X : 0,1 - X : 4 - X x 3/4 = 54
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(x - 0,1)⁶ = (x - 0,1)⁴
(x - 0,1)⁶ - (x - 0,1)⁴ = 0
(x - 0,1)⁴.[(x - 0,1)² - 1] = 0
(x - 0,1)⁴ = 0 hoặc (x - 0,1)² - 1 = 0
*) (x - 0,1)⁴ = 0
x - 0,1 = 0
x = 0,1
*) (x - 0,1)² - 1= 0
(x - 0,1)² = 1
x - 0,1 = 1 hoặc x - 0,1 = -1
**) x - 0,1 = 1
x = 1 + 0,1
x = 1,1
*) x - 0,1 = -1
x = -1 + 0,1
x = -0,9
Vậy x = -0,9; x = 0,1; x = 1,1
X : 0,25 - X = 15,6
X × 4 - X = 15,6
X × (4 - 1) = 15,6
X × 3 = 15,6
X = 15,6 : 3
X = 5,2
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X : 0,1 - X : 4 - X × 3/4 = 2,25
X × 10 - X × 1/4 - X × 3/4 = 2,25
X × (10 - 1/4 - 3/4) = 2,25
X × 9 = 2,25
X = 2,25 : 9
X = 0,25
a.
150 + x : 3 = 620 : 4
150 + x : 3 = 155
x : 3 = 155 - 150
x : 3 = 5
x = 5 x 3
x = 15
b.
x * 0,1 = 1/2 -2/5
x * 1/10 = 5/10 - 4/10
x * 1/10 = 1/10
x = 1/10 : 1/10
x = 1
c.
4/9 + 5/9 : x = 1
5/9 : x = 1 - 4/9
5/9 :x = 5/9
x = 5/9 : 5/9
x = 1
1) \(150+x.\frac{1}{3}=155\)
\(\frac{1}{3}x=5\)
\(x=15\)
2) \(x.\frac{1}{10}=\frac{1}{2}-\frac{2}{5}\)
\(\frac{1}{10}x=\frac{5}{10}-\frac{4}{10}\)
\(\frac{1}{10}x=\frac{1}{10}\)
\(x=1\)
3) \(\frac{4}{9}+\frac{9}{5}x=1\)
\(\frac{9}{5}x=\frac{9}{9}-\frac{4}{9}\)
\(\frac{9}{5}x=\frac{5}{9}\)
\(x=1\)
Ta có : \(x\div0,1-x\div4-x\times\frac{3}{4}=2,25\)
\(\Leftrightarrow x\times10-x\times\frac{1}{4}-x\times\frac{3}{4}\)
\(\Rightarrow x\times\left(10-\frac{1}{4}-\frac{3}{4}\right)=2,25\)
\(\Rightarrow x\times9=2,25\)
\(\Rightarrow x=2,25\div9=0,25\)
a, \(\left(2x-1\right)\left(x+3\right)-2x^2+5x=7\)
\(\Leftrightarrow2x^2+6x-x-3-2x^2+5x=7\)
\(\Leftrightarrow2x^2+5x-3-2x^2+5x=7\)
\(\Leftrightarrow10x-10=0\Leftrightarrow x=1\)
b, \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-4\right)\left(x+4\right)=54\)
\(\Leftrightarrow\left(x^3+27\right)-x\left(x^2-16\right)=54\)
\(\Leftrightarrow x^3+27-x^3+16x=54\)
\(\Leftrightarrow-27+16x=0\Leftrightarrow x=\frac{27}{16}\)
\(x\times4=3429:54\)
\(x\times4=63,5\)
\(x=63,5:4\)
\(x=15,875\)
\(68\times x=2,89:0,1\)
\(68\times x=28,9\)
\(x=28,9:68\)
\(x=0,425\)
a.=> \(\frac{\left(\frac{1}{3}\right).x}{\frac{2}{3}}=\frac{\frac{7}{4}}{\frac{2}{5}}\)
=> \(\frac{1}{3}.x=\frac{7}{4}.\frac{2}{3}:\frac{2}{5}\)
=>\(\frac{1}{3}.x=\frac{35}{12}\)
=> x\(=\frac{35}{12}:\frac{1}{3}\)
Vậy x=\(\frac{35}{4}\).
b. => \(\frac{4,5}{0,3}=\frac{2,25}{0,1.x}\)
=>\(0,1.x=\frac{2,25.0,3}{4,5}\)
=>\(0,1.x=0,15\)
=>\(x=0,15:0,1\)
Vậy x=1,5
c. =>\(\frac{8}{\frac{1}{4}.x}=\frac{2}{0,02}\)
=>\(\frac{1}{4}.x=\frac{8.0,02}{2}\)
=>\(\frac{1}{4}.x=0,08\)
=>\(x=0,08:\frac{1}{4}\)
Vậy x=0,32.
d. =>\(\frac{3}{\frac{9}{4}}=\frac{\frac{3}{4}}{6.x}\)
=>\(3.6x=\frac{9}{4}.\frac{3}{4}\)
=>\(18x=\frac{27}{16}\)
=>\(x=\frac{27}{16}:18\)
Vậy x=\(\frac{3}{32}\)
1: \(\Leftrightarrow x=UCLN\left(24;36;150\right)=6\)
2: \(\Leftrightarrow x\in\left\{24;48;72;...\right\}\)
mà 16<=x<=50
nên \(x\in\left\{24;48\right\}\)
3: \(\Leftrightarrow x\inƯ\left(6\right)\)
mà x>-10
nên \(x\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
4: \(\Leftrightarrow x\in BC\left(4;5;8\right)\)
\(\Leftrightarrow x\in\left\{...;-40;0;40;80;120;160;200;...\right\}\)
mà -20<x<180
nên \(x\in\left\{0;40;80;120;160\right\}\)