2/5x8 + 2/8x11 + 2/11x14 + ... + 2/95x98
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\(A=\dfrac{2}{5\times8}+\dfrac{2}{8\times11}+\dfrac{2}{11\times14}+...+\dfrac{2}{95\times98}\)
\(=2\times\dfrac{1}{3}\times\left(\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}+...+\dfrac{1}{95}-\dfrac{1}{98}\right)\)
\(=\dfrac{2}{3}\times\left(\dfrac{1}{5}-\dfrac{1}{98}\right)\)
\(=\dfrac{2}{3}\times\dfrac{93}{490}\)
\(=\dfrac{31}{245}\)
\(\dfrac{2}{5x8}\) + \(\dfrac{2}{8x11}\) + \(\dfrac{2}{11x14}\)+........+\(\dfrac{2}{95x98}\)
\(\frac{2}{5\times8}+\frac{2}{8\times11}+\frac{2}{11\times14}+...+\frac{2}{95\times98}\)
\(=\left(\frac{3}{5\times8}+\frac{3}{8\times11}+\frac{3}{11\times14}+...+\frac{3}{95\times98}\right)\times\frac{2}{3}\)
\(=\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{95}-\frac{1}{98}\right)\times\frac{2}{3}\)
\(=\left(\frac{1}{5}-\frac{1}{98}\right)\times\frac{2}{3}\)
\(=\frac{93}{490}\times\frac{2}{3}\)
\(=\frac{93\times2}{490\times3}\)
\(=\frac{31\times1}{245\times1}\)
\(=\frac{31}{245}\)
2/5x8+2/8x11+2/11x14+...+2/95x98
=2(1/5x8+1/8x11+1/11x14+...+1/95x98) (khoang cach tu 5-8;8-11;11-14;...;95-98 la 3) suy ra =2/3(1/5-1/8+1/8-1/11+1/11-1/14+...+1/95-1/98)
=2/3(1/5-1/98)=2/3x93/5x98=31/245
top scorer cop tại:tính nhanh:2/2*5+2/5*8+2/8*11+2/11*14+2/14*17? | Yahoo Hỏi & Đáp
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\(A=\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{92.95}+\frac{1}{95.98}\)
\(A=\frac{1}{3}\cdot\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{92.95}+\frac{3}{95.98}\right)\)
\(A=\frac{1}{3}\cdot\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{95}-\frac{1}{98}\right)\)
\(A=\frac{1}{3}\cdot\left(\frac{1}{2}-\frac{1}{98}\right)\)
\(A=\frac{1}{3}\cdot\frac{24}{49}\)
\(A=\frac{8}{49}\)
Đề sai rồi bạn nhé, đề là như thế này:
\(A=\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{92.95}+\frac{1}{95.98}\)
\(A=\frac{1}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{92.95}+\frac{3}{95.98}\right)\)
\(A=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{92}-\frac{1}{95}+\frac{1}{95}-\frac{1}{98}\right)\)
\(A=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{98}\right)\)
\(A=\frac{1}{3}.\frac{24}{49}\)
\(A=\frac{24}{147}=\frac{8}{49}\)
A=1/5-1/8+1/8-1/11+...+1/602-1/605
=1/5-1/605
=24/121
Ta có : A=3/2x5+3/5x8+3/8x11+3/11x14+3/14x17+3/17x20
=> A=1/2-1/5+1/5-1/8+1/8-1/11+1/11-1/14+1/14-1/17+1/17-1/20
=> A=1/2-1/20
=> A=9/20
Vậy A=9/20
đó
Không biết làm nha. Mai đến lớp cô chữa
$\frac{2}{5\times 8}+\frac{2}{8\times 11}+\frac{2}{11\times 14}+...+\frac{2}{95\times 98}$
$=\left(\frac{3}{5\times 8}+\frac{3}{8\times 11}+\frac{3}{11\times 14}+...+\frac{3}{95\times 98}\right)\times \frac{2}{3}$
$=\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{95}-\frac{1}{98}\right)\times \frac{2}{3}$
$=\left(\frac{1}{5}-\frac{1}{98}\right)\times \frac{2}{3}$
$=\frac{93}{490}\times \frac{2}{3}$
$=\frac{93\times 2}{490\times 3}$
$=\frac{31\times 1}{245\times 1}$
$=\frac{31}{245}$