25+30-16+32=?
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\(\dfrac{7}{16}+\dfrac{-1}{8}+\dfrac{9}{32}=\dfrac{14}{32}-\dfrac{4}{32}+\dfrac{9}{32}=\dfrac{19}{32}\)
\(\dfrac{5}{4}-\dfrac{25}{30}\times\dfrac{37}{44}+\dfrac{-25}{30}\times\dfrac{13}{44}+\dfrac{-25}{30}\times\dfrac{-6}{44}\)
\(=-\dfrac{25}{30}\times\left(\dfrac{5}{4}+\dfrac{37}{44}+\dfrac{13}{44}-\dfrac{6}{44}\right)\)
\(=-\dfrac{25}{30}\times\left(\dfrac{55}{44}+\dfrac{37}{44}+\dfrac{13}{44}-\dfrac{6}{44}\right)\)
\(=-\dfrac{25}{30}\times\dfrac{99}{44}\)
\(=-\dfrac{5}{6}\times\dfrac{9}{4}\)
\(=-\dfrac{15}{8}\)
\(\left(\dfrac{7}{16}+\dfrac{-1}{8}+\dfrac{9}{32}\right):\dfrac{5}{4}\)
\(=\left(\dfrac{14}{32}+\dfrac{-4}{32}+\dfrac{9}{32}\right):\dfrac{5}{4}\)
\(=\dfrac{19}{32}:\dfrac{5}{4}\)
\(=\dfrac{19}{32}.\dfrac{4}{5}=\dfrac{19.4}{32.5}=\dfrac{19}{40}\)
\(\dfrac{-25}{30}.\dfrac{37}{44}+\dfrac{-25}{30}.\dfrac{13}{44}+\dfrac{-25}{30}.\dfrac{-6}{44}\)
\(=\dfrac{-25}{30}.\left(\dfrac{37}{44}+\dfrac{13}{44}+\dfrac{-6}{44}\right)\)
\(=\dfrac{-25}{30}.\dfrac{44}{44}=\dfrac{-5}{6}.1=-\dfrac{5}{6}\)
\(=\dfrac{3^{30}\cdot2^{100}}{2^{30}\cdot3^{30}\cdot2^{75}}=\dfrac{1}{2^5}=\dfrac{1}{32}\)
a,16+25+30+54
=(16+54)+(25+30)
=70+55
=125
b,25+43+57+32
=(25+32)+(43+57)
=57+100
=157
16 + 25 + 30 + 54
= ( 16 + 54 ) + (25 + 30 )
= 70 + 55
= 125
25 + 43 + 57 + 32
= ( 43 + 57 ) + ( 25 + 32 )
= 100 + 57
= 157
Đặt giá trị biểu thức là A, ta có:
\(A=\dfrac{\left(-27\right)^{10}.16^{25}}{6^{30}.\left(-32\right)^{15}}\)
\(A=\dfrac{\left(\left(-3\right)^3\right)^{10}.\left(2^4\right)^{25}}{2^{30}.3^{30}.\left(\left(-2\right)^5\right)^{15}}\)
\(A=\dfrac{\left(-3\right)^{30}.2^{100}}{2^{30}.3^{30}.\left(-2\right)^{75}}\)
\(A=\dfrac{3^{30}.2^{100}}{2^{30}.2^{75}.3^{30}}=\dfrac{1}{2^5}=\dfrac{1}{32}\)
(25-32)-(7+x)=47-25
-7 - ( 7 + x ) = 22
-7 - 7 - x = 22
- 14 - x = 22
x = 22 + ( - 14 )
x = 8
3x - 16 = 40 + x
3x - x = 40 + 16
2x = 56
x = 56 : 2
x = 28
-4 . | 2x - 3 | = ( - 16 ) : | - 4 |
-4 . | 2x - 3 | = ( - 16 ) : 4
-4 . | 2x - 3 | = -4
| 2x -3 | = -4 : ( - 4 )
| 2x - 3 | = 1
=> \(\orbr{\begin{cases}2x-3=1\\2x=3=-1\end{cases}\Rightarrow\orbr{\begin{cases}2x=1+3=4\\2x=-1+3=2\end{cases}\Rightarrow}\orbr{\begin{cases}x=4:2=2\\x=2:2=1\end{cases}}}\)
Vậy x = 2 hoặc 1
\(\frac{16^{12}.5^{30}.125^6}{32^{10}.81^7.25^{23}}=\frac{2^{48}.3^{30}.5^{30}.5^{18}}{2^{50}.3^{28}.5^{46}}\)
\(=\frac{2^{48}.3^{28}.3^2.5^{46}.5^2}{2^{48}.2^2.3^{28}.5^{46}}\)
=\(\frac{3^2.5^2}{2^2}\)
1: UCLN(12;18)=6
BCNN(12;18)=36
2: UCLN(24;48)=24
BCNN(24;48)=48
a) 81 + 243 + 19 = (81 + 19) + 243
= 100 + 143 = 243
b) 168 + 79 + 132 = (168 + 132) + 79
= 300 + 79 = 379
c) 5 x 25 x 2 x 16 x 4 = (5 x 2) x (25 x 4) x 16
= 10 x 100 x 16 = 16000
d) 32 x 47 + 32 x 53 = 32 x (47 + 53)
= 32 x 100 = 3200
e) 26 + 27 + 28 + 29 + 30 + 31 + 32 = (26 + 32) + (27 + 31) + (28 + 30) + 29
= 58 + 58 + 58 + 29
= 58 x 3 + 29 = 174 + 29 = 203
25+30-16+32=71