Tính:
a.A=4+2^2+2^3+2^4+...+2^20
b,Tìm x biết:(x+1)+(x+2)+...+(x+100)=5750
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\(\left(x-1\right)^2+\left(y+2\right)^2=0\)
Vì \(\left(x-1\right)^2\ge0\forall x\)
\(\left(y+2\right)^2\ge0\forall y\)
Nên \(\left(x-1\right)^2+\left(y+2\right)^2\ge0\) \(\Leftrightarrow\orbr{\begin{cases}\left(x-1\right)^2=0\\\left(y+2\right)^2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x-1=0\\y+2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1\\y=-2\end{cases}}\)
Vậy x = 1 và y = -2
\(1) 420+65.4=(x+175):5+30\)
\(\implies 420+260=(x+175):5+30\)
\(\implies 680=(x+175):5+30\)
\(\implies 650=(x+175):5\)
\(\implies 650.5-175=x\)
\(\implies 3075=x\)
\(2)x-4867=(175.2050.70):25+23\)
\(\implies x-4867=1004500+23\)
\(\implies x-4867=1004523\)
\(\implies x=1009390\)
\(3) 134-[(96-7x):4-2]=126\)
\(\implies (96-7x):4-2=8\)
\(\implies(96-7x):4=10\)
\(\implies 96-7x=40\)
\(\implies 7x=56\)
\(\implies x=8\)
\(4) 4-\{100-[(100-5x):8-5]:10\}:25=0\)
\(\implies 4-\{100-[(100-5x):8-5]:10\}=0\)
\(\implies 100-[(100-5x):8-5]:10=4\)
\(\implies 100-[(100-5x):8-5]=40\)
\(\implies (100-5x):8-5=60\)
\(\implies (100-5x):8=65\)
\(\implies 100-5x=520\)
\(\implies 5x=-420\)
\(\implies x=-84\)
~ Hok tốt a~
1.
7/15:(1/2-9/10xX)-1/6=13/6
=>7/15:(1/2-9/10xX)=13/6+1/6
=>7/16:(1/2-9/10xX)=7/3
=>1/2-9/10xX=7/16:7/3
=>1/2-9/10xX=3/16
=>9/10xX=1/2-3/16
=>9/10xX=5/16
=>X=5/16:9/10
=>X=25/72
\(-3x\left(x+2\right)^2+\left(x+3\right)\left(x-1\right)\left(x+1\right)-\left(2x-3\right)^2\)
\(=-3x\left(x^2+4x+4\right)+\left(x+3\right)\left(x^2-1\right)-\left(4x^2-12x+9\right)\)
\(=-3x^3-12x^2-12x+x^3-x+3x^2-3-4x^2+12x-9\)
\(=-2x^3-13x^2-x-12\)
mình bik giải câu b thôi
TA CÓ
(x+1)+(x+2)+.................+(x+100)=5750
x+1+x+2+..............+x+100=5750
(x+x+....+x)+(1+2+3+.......+100)=5750
100.x + 5050 =5750
100.x=5750-5050
100x=700
=>x=700:100=7
VẬY X = 7
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