tìm x
x : 5 = 20
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\(x-\dfrac{3}{20}=x+\dfrac{1}{5}\)
\(\Leftrightarrow0=\dfrac{1}{5}+\dfrac{3}{20}\left(voli\right)\)
Vậy pt vô nghiệm
-4x+\(\dfrac{17}{20}=\dfrac{5}{4}\)
=>-4x=\(\dfrac{5}{4}-\dfrac{17}{20}\)
=>-4x=\(\dfrac{25-17}{20}\)
=>-4x=\(\dfrac{8}{20}=\dfrac{2}{5}\)
=>x=\(\dfrac{2}{5}.\dfrac{1}{4}\)
=>x=\(\dfrac{2}{20}=\dfrac{1}{10}\)
Vậy .....
x(100%+20%)=7.2
x120%=720%
x=720%:120%
x=6
vậy////////
(40%+100%)x+20%=720%
140%x=720%-20%
140%x=700%
x=720%:140%
x=36/7
vậy x=/////////////
\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)
\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)
\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)
\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)
\(\dfrac{3}{4}-x=\dfrac{91}{66}\)
\(x=\dfrac{-83}{132}\)
\(x^2\left(x-5\right)+x-5=0\)
\(\Rightarrow x^2\left(x-5\right)+\left(x-5\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x^2-1\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x-1\right)\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-5=0\\x-1=0\\x+1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=5\\x=1\\x=-1\end{matrix}\right.\)
\(x^2\left(x-5\right)+x-5=0\)
\(\Leftrightarrow x-5=0\)
hay x=5
x : 5 = 20
x = 20 : 5
x = 4
Chúc bn học tốt!!
x = 100