12x^2+7x-12
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
*) (-7) - (-12) + (-5)
= [(-7) + (-5)] + 12
= (-12) + 12
= 0
*) (-2) . 32 + 7 . (-4) - (-34)
= (-2) . 9 + (-28) + 34
= -18 + (-28) + 34
= -46 + 34
= -12
*) 12 . (-82) + (-12).18
= (-12) . 82 + (-12) . 18
= (-12) . (82 + 18)
= (-12) . 100
= -1200
2x^2 + x - 6
= 2x^2 + 4x - 3x - 6
= 2x(x + 2) - 3(x + 2)
= (2x - 3)(x + 2)
7x^2 + 50x + 7
= 7x^2 + x + 49x + 7
= 7x(x + 7) + x + 7
= (7x + 1)(x + 7)
12x^2 + 7x - 12
15x^2 + 7x - 2
= 15x^2 - 3x + 10x - 2
= 3x(5x - 1) + 2(5x - 1)
= (3x + 2)(5x - 1)
a^2 - 5a - 14
= a^2 + 2a - 7a - 14
= a(a + 2) - 7(a + 2)
= (a - 7)(a + 2)
2x^2 + 5x + 2
= 2x^2 + x + 4x + 2
= 2x(x + 2) + x + 2
= (2x + 1)(x + 2)
\(2x^2+x-6=2x^2+4x-3x-6\)
\(=2x\left(x+2\right)-3\left(x+2\right)\)
\(=\left(x+2\right)\left(2x-3\right)\)
\(7x^2+50x+7\)
\(=7x^2+x+49x+7\)
\(=x\left(7x+1\right)+7\left(7x+1\right)\)
\(=\left(7x+1\right)\left(x+7\right)\)
\(12x^2+7x-12\)
\(=12x^2+16x-9x-12\)
\(=4x\left(3x+4\right)-3\left(3x+4\right)\)
\(=\left(3x+4\right)\left(4x-3\right)\)
\(12x^2+7x-12\)
\(=12x^2-9x+16x-12\)
\(=3x\left(4x-3\right)+4\left(4x-3\right)\)
\(=\left(4x-3\right)\left(3x+4\right)\)
12x^2+7x-12=(12x^2-9x)+(16x-12)=3x(4x-3)+4(4x-3)=(3x+4)(4x-3)
chúc hok tốt
\(12x^2+7x-12=12x^2-9x+16x-12=3x\left(4x-3\right)+4\left(4x-3\right)\)
\(=\left(3x+4\right)\left(4x-3\right)\)
\(x^2-5x+6=\left(x-2\right)\left(x-3\right)\)
\(x^2-7x+12=\left(x-2\right)\left(x-5\right)\)
\(x^2+x-12=\left(x-5\right)\left(x+6\right)\)
\(x^2-9x+20=\left(x-4\right)\left(x-5\right)\)
12x2 + 7x - 12
= 12x2 + 16x - 9x - 12
= 4x.( 3x + 4 ) - 3.( 3x + 4 )
= ( 3x + 4 ).( 4x - 3 )
\(12x^2+7x-12\)
\(=12x^2+16x-9x-12\)
\(=4x\left(3x+4\right)-3\left(3x+4\right)\)
\(=\left(4x-3\right)\left(3x+4\right)\)
=12x^2+16x-9x-12
=4x*(3x+4)-3*(3x+4)
=(3x+4)*(4x-3)