Giúp mình câu 9 10 11 12 với ạ 
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
NP
2
26 tháng 9 2021
\(8,\\ A=\left\{0;1;2;3\right\}\\ B=\left\{0;1;2\right\}\\ A\cap B=\left\{0;1;2\right\}\\ A\cup B=\left\{0;1;2;3\right\}\\ A\B=\left\{3\right\}\\ B\A=\varnothing\\ 9,\\ A=\left\{0;1;2;3;4\right\}\\ B=\left\{5;6\right\}\\ A\cap B=\varnothing\\ A\cup B=\left\{0;1;2;3;4;5;6\right\}\\ A\B=\left\{0;1;2;3;4\right\}\\ B\A=\left\{5;6\right\}\)
PT
GIÚP MÌNH CÂU 4,CÂU 5, CÂU 9, CÂU 11, CÂU 12 VÀ CÂU 15 THÔI Ạ!!
1
DT
Đỗ Thanh Hải
CTVVIP
11 tháng 7 2021
4 If you aren't alert, you computer will be infected with viruses
5 If we use much pesticide on vegetables, they will become poisonous
9 Because Nam needs to improve his social skills, he attends the activity
11 How about using public buses instead of motorbike
12 They enjoy protecting the environment unpolluted
15 Mr Brown was disappointed that his son didn't write to him
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
10 tháng 8 2023
\(\dfrac{21}{36}-\left(-\dfrac{11}{30}\right)=\dfrac{7}{12}+\dfrac{11}{30}=\dfrac{7.5+11.2}{60}=\dfrac{57}{60}=\dfrac{19}{20}\\ ----\\\dfrac{-4}{8}+\left(-\dfrac{3}{10}\right)=\dfrac{-1}{2}-\dfrac{3}{10}=\dfrac{-1.5-3}{10}=\dfrac{-8}{10}=-\dfrac{4}{5}\\ ----\\ \dfrac{7}{12}-\left(-\dfrac{9}{20}\right)=\dfrac{7}{12}+\dfrac{9}{20}=\dfrac{7.5+9.3}{60}=\dfrac{62}{60}=\dfrac{31}{30}\\ ---\\ \dfrac{-2}{5}+\left(-\dfrac{11}{30}\right)=-\dfrac{2}{5}-\dfrac{11}{30}=\dfrac{-2.6-11}{30}=-\dfrac{29}{30}\)
23 tháng 2 2022
\(\dfrac{5}{11}+\dfrac{4}{11}=\dfrac{9}{11}\\ \dfrac{11}{10}+\dfrac{9}{10}=\dfrac{20}{10}=2\\ \dfrac{11}{12}+\dfrac{5}{12}=\dfrac{16}{12}=\dfrac{4}{3}\\ \dfrac{7}{9}+\dfrac{5}{9}=\dfrac{12}{9}=\dfrac{4}{3}\)
23 tháng 2 2022
\(\dfrac{5}{11}+\dfrac{4}{11}=1\)
\(\dfrac{11}{10}+\dfrac{9}{10}=\dfrac{20}{10}=2\)
\(\dfrac{11}{12}+\dfrac{5}{12}=\dfrac{16}{12}=\dfrac{4}{3}\)
\(\dfrac{7}{9}+\dfrac{5}{9}=\dfrac{12}{9}=\dfrac{4}{3}\)
8 tháng 4 2023
1)\(\dfrac{2}{9}+\dfrac{-3}{4}+\dfrac{5}{30}\)
\(=\dfrac{2.20}{9.20}+\dfrac{-3.45}{4.45}+\dfrac{5.6}{30.6}\)
\(=\dfrac{40}{180}+\dfrac{-135}{180}+\dfrac{30}{180}\)
\(=\dfrac{40+\left(-135\right)+30}{180}\)
\(=\dfrac{-65}{180}\)
\(=\dfrac{-13}{36}\)
2)\(\dfrac{-7}{12}-\dfrac{11}{18}\)
\(=\dfrac{-7.3}{12.3}-\dfrac{11.2}{18.2}\)
\(=\dfrac{-21}{36}-\dfrac{22}{36}\)
\(=\dfrac{-21-22}{36}\)
\(=\dfrac{-43}{36}\)
3)\(\dfrac{7}{8}-\dfrac{-5}{16}\)
\(=\dfrac{7.2}{8.2}-\dfrac{-5}{16}\)
\(=\dfrac{14}{16}-\dfrac{-5}{16}\)
\(=\dfrac{14-\left(-5\right)}{16}\)
\(=\dfrac{19}{16}\)
4)\(\dfrac{3}{8}-\dfrac{-9}{10}-\dfrac{5}{16}\)
\(=\dfrac{3.10}{8.10}-\dfrac{-9.8}{10.8}-\dfrac{5.5}{16.5}\)
\(=\dfrac{30}{80}-\dfrac{-72}{80}-\dfrac{25}{80}\)
\(=\dfrac{30-\left(-72\right)-25}{80}\)
\(=\dfrac{77}{80}\)
cÂU 9.
\(I=\dfrac{\xi}{r+R_N}=\dfrac{20}{5+10}=\dfrac{4}{3}A\)
\(P_R=I^2_R\cdot R=\dfrac{4}{3}\cdot10=\dfrac{40}{3}W\)
\(P=\xi\cdot I=20\cdot\dfrac{4}{3}=\dfrac{80}{3}W\)
\(H=\dfrac{R}{r+R}=\dfrac{10}{5+10}=\dfrac{2}{3}\approx66,67\%\)