x + 24 + x x + 24 − x < 27 8 . 12 + x − x 2 + 24 x 12 + x + x 2 + 24 x . Tập nghiệm của bất phương trình
A. 0 ≤ x ≤ 1.
B. x ≥ 0.
C. 0 ≤ x ≤ 1 2 .
D. 0 ≤ x < 1.
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12 x 50 + 8 x 27 + 6 x 52 + 24 x 53
= 24 x 25 + 24 x 9 + 24 x 13 + 24 x 53
= 24 x ( 25 + 9 + 13 + 53 )
=24 x100
= 2400
12 x 50 + 8 x 27 + 6 x 52 + 24 x 53
=24 x 25 + 24 x 9 +24 x 13 + 24 x 53
=24 x(25 + 9 + 13 + 53)
=24x100
=2400
17 - 2x = -15
2x = 17 - (-15)
2x = 32
x = 32 : 2
x = 16
--------
54 : (x + 2) = -6
x + 2 = 54 : (-6)
x + 2 = -9
x = -9 - 2
x = -11
--------
12.(3 - x) = 72
3 - x = 72 : 12
3 - x = 6
x = 3 - 6
x = -3
-------
-3(x + 5) + 18 = -27
-3(x + 5) = -27 - 18
-3(x + 5) = -45
x + 5 = -45 : (-3)
x + 5 = 15
x = 15 - 5
x = 10
-------
(x + 5)² = 9
x + 5 = 3 hoặc x + 5 = -3
*) x + 5 = 3
x = 3 - 5
x = -2
*) x + 5 = -3
x = -3 - 5
x = -8
Vậy x = -8; x = -2
--------
(3 - x)³ = 27
(3 - x)³ = 3³
3 - x = 3
x = 3 - 3
x = 0
a: \(=\dfrac{2^{19}\cdot3^9+2^{20}\cdot3^{10}}{2^{19}\cdot3^9+2^{18}\cdot3^9\cdot5}=\dfrac{2^{19}\cdot3^9\left(1+2\cdot3\right)}{2^{18}\cdot3^9\left(2+5\right)}=2\)
A = 8 . 12 . 32 + 4 . 27 . 24 + 41 .4 . 16
A = 96 . 32 + 96 . 27 + 41 . 4 . 16
A = 96 ( 32 + 27 ) +41 . 4 . 16
A = 96 . 59 + 41 . 64
A = 32 . 3 . 59 + 41 . 32 . 2
A = 32 ( 3 + 59 + 41 + 2 )
A = 32 . 105
A = 3360
8 x 12 x 32 + 4 x 27 x 24 + 41 x 6 x 16
=96 x 32 + 96 x 27 + 96 x 41
=96 x (32 + 27 + 41)
= 96 x 100
=9600
A = 8 × 12 × 32 + 4 × 27 × 24 + 41 × 6 × 16
A = 8 × 12 × 32 + 4 × 24 × 27 + 6 × 16 × 41
A = 96 × 32 + 96 × 27 + 96 × 41
A = 96 × (32 + 27 + 41)
A = 96 × 100
A = 9600
A = \(\dfrac{8\times12\times32+4\times27\times24+96\times41}{16\times48-48\times9+4\times3\times12}\)
A = \(\dfrac{96\times32+96\times27+96\times41}{16\times48-48\times9+48\times3}\)
A = \(\dfrac{96\times\left(32+27+41\right)}{48\times\left(16-9+3\right)}\)
A = \(\dfrac{96\times100}{48\times10}\)
A = \(\dfrac{20}{1}\) \(\times\) \(\dfrac{48\times10}{48\times10}\)
A = 20
\(\frac{x^{24}+x^{18}+x^{12}+x^6+1}{x^{27}+x^{24}+x^{21}+x^{18}+x^{15}+x^{12}+x^9+x^6+x^3+1}=\frac{x^{24}+x^{18}+x^{12}+x^6+1}{x^{24}\left(x^3+1\right)+x^{18}\left(x^3+1\right)+x^{12}\left(x^3+1\right)+x^6\left(x^3+1\right)+\left(x^3+1\right)}\)
=\(\frac{x^{24}+x^{18}+x^{12}+x^6+1}{\left(x^3+1\right)\left(x^{24}+x^{18}+x^{12}+x^6+1\right)}=\frac{1}{x^3+1}\)
a)\(\dfrac{x}{60}=-\dfrac{3}{4}\)
\(\Rightarrow x\cdot4=60\cdot\left(-3\right)\)
\(x\cdot4=-180\)
x=45
b)\(\dfrac{2}{5}=\dfrac{12}{x}\)
\(\Rightarrow2x=5\cdot12\)
\(2x=60\)
x=30
c)\(x-\dfrac{5}{7}=\dfrac{6}{21}\)
\(x=\dfrac{2}{7}+\dfrac{5}{7}\)
x=1
d)\(x+\dfrac{7}{8}=\dfrac{63}{24}\)
\(x=\dfrac{21}{8}-\dfrac{7}{8}\)
\(\dfrac{14}{8}\)
Đáp án là D