ai đó giải giúp với xin cả mơn nhiều
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N
11 tháng 11 2021
Bài 1:
a. \(R=p\dfrac{l}{S}=1,10.10^{-6}\dfrac{30}{0,3\cdot10^{-6}}=110\Omega\)
b. \(I=U:R=220:110=2A\)
Bài 2:
a. \(R=R1+R2=30+50=80\Omega\)
b. \(I=I1=I2=0,25A\left(R1ntR2\right)\)
\(\left\{{}\begin{matrix}U1=I1\cdot R1=0,25\cdot30=7,5V\\U2=I2\cdot R2=0,25\cdot50=12,5V\\U=IR=0,25\cdot80=20V\end{matrix}\right.\)
11 tháng 11 2021
Câu 1.
a)\(R=\rho\cdot\dfrac{l}{S}=1,1\cdot10^{-6}\cdot\dfrac{30}{0,3\cdot10^{-6}}=110\Omega\)
b)\(I=\dfrac{U}{R}=\dfrac{220}{110}=2A\)
Câu 2.
a)\(R_{AB}=R_1+R_2=30+50=80\Omega\)
b)\(I_1=I_2=I_A=0,25A\)
\(U_1=R_1\cdot I_1=30\cdot0,25=7,5V\)
\(U_2=R_2\cdot I_2=50\cdot0,25=12,5V\)
\(U_{AB}=U_1+U_2=7,5+12,5=20V\)
Câu 3.
a)\(R_{AB}=\dfrac{R_1\cdot R_2}{R_1+R_2}=\dfrac{600\cdot900}{600+900}=360\Omega\)
b)\(U_1=U_2=U_m=220V\)
\(I_1=\dfrac{U_1}{R_1}=\dfrac{220}{600}=\dfrac{11}{30}A\)
\(I_2=\dfrac{U_2}{R_2}=\dfrac{220}{900}=\dfrac{11}{45}A\)
\(I_m=I_1+I_2=\dfrac{11}{30}+\dfrac{11}{45}=\dfrac{11}{18}A\)
DP
2
H
11 tháng 11 2021
1. In spite of being a poor student, he studied very well
2. Despite the bad weather, she went to school on time
3. Despite having a physical handicap, she has become a successful woman
4. In spite of having not finished the paper, he went to sleep
5. Despite having a lot of noise in the city, I prefer living there
11 tháng 11 2021
1. In spite of being a poor student, he studied very well
2. Despite the fact that the weather was bad, she went to school on time.
DP
0
0P
0
H
12 tháng 11 2021
1. Because of studying hard, I passed the exam
2. Because of Hoa's richness, she could buy that house
3. Because of bad grades, she failed the University entrance exam
4. Because of the accident, I was late
5. Because of the terrible traffic, we didn't arrive until 6 o'clock
22 tháng 8 2021
Ta có: \(\sqrt{\dfrac{3\sqrt{5}-1}{2\sqrt{5}+3}}-\sqrt{\dfrac{\sqrt{5}+11}{7-2\sqrt{5}}}\)
\(=\sqrt{\dfrac{\left(3\sqrt{5}-1\right)\left(2\sqrt{5}-3\right)}{11}}-\sqrt{\dfrac{\left(11+\sqrt{5}\right)\left(7+2\sqrt{5}\right)}{29}}\)
\(=\sqrt{\dfrac{11\cdot\left(30-9\sqrt{5}-2\sqrt{5}+3\right)}{121}}-\sqrt{29\cdot\left(\dfrac{77+22\sqrt{5}+7\sqrt{5}+20}{841}\right)}\)
\(=\dfrac{\sqrt{363-121\sqrt{5}}}{11}+\dfrac{\sqrt{2813+841\sqrt{5}}}{29}\)
\(=\dfrac{\sqrt{726-242\sqrt{5}}}{11\sqrt{2}}+\dfrac{\sqrt{5626+1682\sqrt{5}}}{29\sqrt{2}}\)
Bạn tách ra đi nhé! Chứ Sử mà như lày thì chết :v