Tính bằng cách thuận tiện nhất:
2-3/7-4/7
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`2/5 xx 4/7 + 3/5 xx 4/7`
`= 4/7 xx (2/5 + 3/5)`
`= 4/7 xx 1`
`= 4/7`
\(\dfrac{4}{7}x\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{4}{7}x1=\dfrac{4}{7}\)
a, \(=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{3}{5}+\dfrac{3}{5}\right)=1+\dfrac{6}{5}=\dfrac{5+6}{5}=\dfrac{11}{5}\)
\(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{7}+\dfrac{6}{7}\)
\(=\dfrac{1+2+3+4+5+6}{7}=3\)
\(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{7}+\dfrac{6}{7}\)
\(=\left(\dfrac{1}{7}+\dfrac{6}{7}\right)+\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)
\(=1+1+1\)
\(=3\)
`3/7+2/5+4/7`
`=(3/7+4/7)+2/5`
`=1+2/5`
`=5/5+2/5`
`=7/5`
`20/34+4/9+7/17`
`=(20/34+7/17)+4/9`
`=(20/34+14/34)+4/9`
`=34/34+4/9`
`=1+4/9`
`=9/9+4/9`
`=13/9`
`48xx2+96+48xx6`
`=48xx2+48xx2+48xx6`
`=48xx(2+2+6)`
`=48xx10`
`=480`
câu thứ hai thì làm như này em nhé:
\(\dfrac{20}{34}\) + \(\dfrac{4}{9}\) + \(\dfrac{7}{17}\)
= (\(\dfrac{20}{34}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)
= (\(\dfrac{10}{17}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)
= 1 + \(\dfrac{4}{9}\)
= \(\dfrac{13}{9}\)
2 - 3/7 - 4/7
2- ( 3/7 + 4/7)
2 - 1
1
chúc bạn học tốt
\(2-\frac{3}{7}-\frac{4}{7}\)
\(=\)\(2-\left(\frac{3}{7}+\frac{4}{7}\right)\)
\(=\)\(2-1\)
\(=\)\(1\)