ai giúp mình với ạ , cảm ơn nhìu
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
N
1
ai giúp mình phần 1 với ạ
TT
2
18 tháng 12 2016
Tham khảo nhé :
- Once upon a time, hence he has two brothers, who he is extremely greedy, the gentle brother hard. After his parents died he married people in particular have all the wealth plundered and people just leave me a star fruit tree in the corner of the garden.
The younger brother has not been a division of property complaints, building tree huts near indenture. Every day, people you fertilize trees and hired contract to earn money for themselves.
Star fruit trees to have grown, he suddenly wrong laden years. So glad brother.
One day, suddenly there where strange bird flying to the tree and eat indenture contract of em. Seeing this brother with bird sad lament. Strange bird replied, "Eat a piece of gold returns three gang carried away bags that contained".
A few days later as promised birds came out to meet him or her to an island a lot of gold, silver and jewels. Brother watched from above the island and took gold filled pocket only three rides on the back iron and returning birds.
The younger brother used to go home to get some gold in exchange for grain to help the needy in the village.
Seeing this, the play and asked him to change the house, his farm to take his brother's contract tree. Brother again not complain and agree to change for him.
That year also wrong tree laden contract strange bird to eat well. Who he also lamented tearfully. Chim responded and promised to go for gold bearing.
The nature of greed, people somehow connected to his wife of six bags of pig iron and contains lots of gold.
A few days later he met him strange bird and brought him to the island full of gold and jewels. Brother took gold on the island packed into their bags carried away six iron.
On the way back, having to carry a lot of gold and silver to fly against the wind, fatigue strange bird wings. Birds urged him to throw off his gold but people refused to listen.
Phoenix exasperating, unbearable heaviness brother knocked it tilted wing greed and gold into the sea. That was the end greedy.
26 tháng 1 2023
a: =>x(x-3)(x+3)=0
=>\(x\in\left\{0;3;-3\right\}\)
b:=>(x-2)(x-2-x-5)=0
=>x-2=0
=>x=2
c:=>(x-3)^2=0
=>x-3=0
=>x=3
d: =>(x-1)(x-6)=0
=>x=1 hoặc x=6
NH
29 tháng 1 2023
a)
\(=\left(\dfrac{x}{x+3}-\dfrac{x^2+9}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{3x+1}{x\left(x-3\right)}-\dfrac{1}{x}\right)\)
\(=\left(\dfrac{x\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}-\dfrac{x^2+9}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{3x+1}{x\left(x-3\right)}-\dfrac{x-3}{x\left(x-3\right)}\right)\)
\(=\left(\dfrac{x^2-3x-x^2-9}{\left(x+3\right)\left(x-3\right)}\right):\left(\dfrac{3x+1-x+3}{x\left(x-3\right)}\right)\)
\(=\dfrac{-3\left(x+3\right)}{\left(x+3\right)\left(x-3\right)}:\dfrac{2x+4}{x\left(x-3\right)}\)
\(=\dfrac{-3}{\left(x-3\right)}\cdot\dfrac{x\left(x-3\right)}{2x+4}\\ =\dfrac{-3x}{2x+4}\)
b)
với `x=-1/2` (tmđk) ta có
\(\dfrac{-3\cdot\left(\dfrac{-1}{2}\right)}{2\cdot\left(-\dfrac{1}{2}\right)+4}=\dfrac{1}{2}\)
c)
để P=x thì
\(\dfrac{-3x}{2x+4}=x\)
\(=>-3x=\left(2x+4\right)\cdot x\)
\(-3x=2x^2+4x\)
\(2x^2+4x+3x=0\)
\(2x^2+7x=0\)
\(x\left(2x+7\right)=0\)
\(=>\left[{}\begin{matrix}x=0\\2x+7=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\left(loại\right)\\x=-\dfrac{7}{2}\left(tm\right)\end{matrix}\right.\)
d)
mik ko bt lm=)
19 tháng 7 2021
Bài 2:
a) Để hàm số đồng biến thì m+1>0
hay m>-1
b) Để hàm số đi qua điểm A(2;4) thì
Thay x=2 và y=4 vào hàm số, ta được:
\(\left(m+1\right)\cdot2=4\)
\(\Leftrightarrow m+1=2\)
hay m=1
c) Để hàm số đi qua điểm B(2;-4) thì
Thay x=2 và y=-4 vào hàm số, ta được:
\(2\left(m+1\right)=-4\)
\(\Leftrightarrow m+1=-2\)
hay m=-3
19 tháng 7 2021
Bài 1:
b) Ta có: \(5\cdot\sqrt{25a^2}-25a\)
\(=5\cdot5\cdot\left|a\right|-25a\)
\(=-25a-25a=-50a\)
9 tháng 7 2023
a: AC=căn 20^2-12^2=16cm
AH=12*16/20=9,6cm
b: ΔABC vuông tại A có AH là đường cao
nên AH^2=HB*HC(hệ thức lượng)
c: ΔABK vuông tại B có BH là đường cao
nên AH*AK=AB^2
ΔABC vuông tại A có AH là đường cao
nên BH*BC=AB^2
=>BH*BC=AH*AK
