42+24+38-4=
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g) (15 + 37) + (52 – 37 – 17) = 15 + 37 + 52 – 37 – 17 = 15 + 52 – 17 = 50 h) (38 – 42 +14) - (38 – 42 - 15) = 38 – 42 +14 - 38 + 42 + 15 = 14 + 15 = 29 i) (27 + 65 ) + (346 - 27- 65) = 27 + 65 + 346 - 27- 65 = 346 k) - (27 + 65) - (346 – 27 - 65) = -27 - 65 - 346 + 27 + 65 = -346 l) (42 – 69 + 17) - (42 + 17) = 42 – 69 + 17 - 42 - 17 = – 69 m) 24. (16 - 5) – 16. (24 – 5 ) = 24. 16 - 24 . 5 - 16 . 24 + 16. 5 = - 24 . 5 + 16. 5 = -8 . 5 = -40 n) (-12). 47 – 12 . 52 + (-12) = -12 (47 - 52 + 1) = -12 . (-4) = 48 p) 51 . (69 - 25) – 69. (51 - 25) = 51 . 69 - 51 . 25 – 69. 51 + 69. 25 = - 51 . 25 + 69. 25 = (- 51+ 69).25 = 450 |
e. = 12 - 25 + 38 + 25 - 38 + 88 - 250
= ( -25 + 25) + (38 - 38) + ( 12 + 88) - 250
= -150
f. = (-12).44 + 44.(-88)
= 44 ( -12 -88 )
= 44 . 100
= 4400
g. = -48 + 54 -77 -24 + 48 + 77
= (-48 + 48) + (-77+77) + (54 -24)
= 30
h. = 11.(-42) + 11.(-26) + 42.11 + 42.26 -26.11 - 42.26
= \([11.\left(-42\right)+11.42]+\left[11.\left(-26\right)-26.11\right]+[42.26-42.26]\)
= 11. (-52)
= - 572
\(e.-\left(-12+25-38\right)+\left(25-38+88\right)-250\\ =12-25+38+25-38+88-250\\ =\left(25-25\right)+\left(38-38\right)+\left(12+88\right)-250\\ =0+0+100-250=-150\)
\(f.\left(-12\right)\cdot\left(67-23\right)+44\cdot\left(-88\right)\\ =\left(-12\right)\cdot44+44\cdot\left(-88\right)\\ =44\cdot\left[-12+\left(-88\right)\right]\\ =44\cdot\left(-100\right)=-4400\)
\(g.\left(-48+54-77\right)-\left(24-48-77\right)\\ =-48+54-77-24+48+77\\ =\left(48-48\right)+\left(54-24\right)+\left(77-77\right)\\ =0+30+0=30\)
\(h.11\cdot\left(-42-26\right)+42\cdot\left(11+26\right)-26\cdot11-42\cdot26\\ =11\cdot\left(-68\right)+42\cdot37-26\cdot11-42\cdot26\\ =-748+1554-286-1092=-572\)
a)
\(\left(14^{19}-14^{18}\right)\div\left(14^5\times14^{12}\right)\)
\(=\left(14^{19}-14^{18}\right)\div14^{17}\)
\(=\left(14^{19}-14^{18}\right)\times\dfrac{1}{14^{17}}\)
\(=\dfrac{14^{19}-14^{18}}{14^{17}}=\dfrac{14^{18}\times\left(14-1\right)}{14^{17}}\)
\(=14\times13=182\)
b)
\(\left(2^{41}+3^8\right)\times\left(10^7-2^7\right)\times\left(2^4-4^2\right)\)
\(=\left(2^{41}+3^8\right)\times\left(10^7-2^7\right)\times\left(2^4-2^4\right)\)
\(=\left(2^{41}+3^8\right)\times\left(10^7-2^7\right)\times0\)
\(=0\)
A)\(\dfrac{-33}{-44}\) và \(\dfrac{-42}{-56}\) ta có: -33 x -56=1848 -44 x -42 =1848 \(\Rightarrow\) -33 x-56 = -44 x -42 \(\Rightarrow\) \(\dfrac{-33}{-44}=\dfrac{-42}{-56}\) 19/-38 và -24/96 ta có : 19 x -24 = -456 -38 x 96=-3648 \(\Rightarrow\) 19 x -24 \(\ne\) -38 x 96 \(\Rightarrow\) 19/-38 \(\ne\) -24 / 96
a) 57 + 28 = 85
24 + 67 = 91
46 + 39 = 85
b) 83 - 19 = 64
42 - 38 = 4
90 - 76 = 14
\(\begin{array}{*{20}{c}}{a)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{57}\\{28}\end{array}}\\\hline{\,\,\,\,85}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{24}\\{67}\end{array}}\\\hline{\,\,\,\,91}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{46}\\{39}\end{array}}\\\hline{\,\,\,\,85}\end{array}\)
\(\begin{array}{*{20}{c}}{b)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{83}\\{19}\end{array}}\\\hline{\,\,\,\,64}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{42}\\{38}\end{array}}\\\hline{\,\,\,\,04}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{90}\\{76}\end{array}}\\\hline{\,\,\,\,14}\end{array}\)
42+24+38-4
=66+38-4
=104-4
=100
Hok tốt!
@Kaito Kid
TL :
42 + 24 + 38 - 4
= ( 42 + 38 ) + ( 24 - 4 )
= 80 + 20
= 100
T I C K cho tui !
~HT~