Tìm x
a. ( x -1384) x 2 = 6478
b. 1855 : x = 175 : 5
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a) 162 : 𝑥 + 216 : 𝑥 = 6
(162 + 216) : x = 6
378 : x = 6
x = 378 : 6
x = 63
b) 602 : x + 123 x 2 = 253
602 : x + 246 = 253
602 : x = 253 - 246
602 : x = 7
x = 602 : 7
x = 86
c) 486 : x - 126 :x = 6
(486-126) : x = 6
360 : x = 6
x = 360 : 6
x = 60
d) 725 : x + 175 : x = 5
(725 + 175) : x = 5
900 : x = 5
x = 900 : 5
x = 180
a)\(162:x+216:x=6\)
⇔\(\left(162+216\right):x=6\)
⇔\(378:x=6\)
⇔\(x=63\)
b)\(602:x+123.2=253\)
⇔\(602:x+246=253\)
⇔\(602:x=7\)
⇔\(x=86\)
c)\(486:x-126:x=6\)
⇔\(\left(486-126\right):x=6\)
⇔\(360:x=6\)
⇔\(x=60\)
d)\(725:x+175:x=5\)
⇔\(\left(725+175\right):x=5\)
⇔\(900:x=5\)
⇔\(x=180\)
\(a.162:x+216:x=6\) \(b.602:x+123x2=253\)
\(\left(162+216\right):x=6\) \(602:x+246=253\)
\(378:x=6\) \(602:x=253-246\)
\(x=378:6=63\) \(602:x=7\)
\(x=602:7=86\)
\(c.486:x-126:x=6\) \(d.725:x+175:x=5\)
\(\left(486-126\right):x=6\) \(\left(725+175\right):x=5\)
\(360:x=6\) \(900:x=5\)
\(x=360:6=60\) \(x=900:5=180\)
a) 75*x=1800
x=1800:75
x=24
b) 1855:x=35
x=1855:35
x=53
c)x+x*2+6*x=81
1*x+x*2+6*x=81
x*(1+2+6)=81
x*9=81
x=81:9
x=9
d)155*x-x*146=72
x*(155-146)=72
x*9=72
x=72:9
x=8
*) Ta có:
75 × x = 1800
x = 1800 : 75
x = 24
*) Ta có:
1855 : x = 35
x = 1855 : 35
x = 53
a. Ta có:
75 × x = 1800
x = 1800 : 75
x = 24
b) Ta có:
1855 : x = 35
x = 1855 : 35
x = 53
Đáp số:
a. x = 24,
b. x = 53
Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
3(x+5) -3 = 2(x+1) +7
⇒3x+15-3=2x+2+7
⇒3x+12=2x+9
⇒x=-3
15-(x+2)² = -1
⇒(x+2)2=16
⇒\(\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\)
⇒\(\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)
75-(2x+1)³ =11
⇒(2x+1)³=64⇒\(\left[{}\begin{matrix}2x+1=8\\2x+1=-8\end{matrix}\right.\)⇒\(\left[{}\begin{matrix}x=3,5\\x=-4,5\end{matrix}\right.\)a) ta có: 3(x+5)-3=2(x+1)+7
nên 3x-2x=2+7-15+3
hay x=-3
b) Ta có: \(15-\left(x+2\right)^2=-1\)
nên \(\left(x+2\right)^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)
a) 75 x X = 1800
X = 1800 : 75
X =24
b) 1855 : x = 35
X = 1855 : 35
X = 53