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a) \(x:\frac{1}{2}+\frac{3}{4}=1\frac{19}{20}\)
\(x:\frac{1}{2}+\frac{3}{4}=\frac{39}{20}\)
\(x:\frac{1}{2}=\frac{39}{20}-\frac{3}{4}\)
\(x:\frac{1}{2}=\frac{39}{20}-\frac{15}{20}\)
\(x:\frac{1}{2}=\frac{24}{20}\)
\(x=\frac{24}{20}.\frac{1}{2}\)
\(x=\frac{3}{5}\)
\(x:\frac{1}{2}+\frac{3}{4}=1\frac{19}{20}\)
\(x:\frac{1}{2}=1\frac{19}{20}-\frac{3}{4}\)
\(x:\frac{1}{2}=\frac{39}{20}-\frac{3}{4}\)
\(x:\frac{1}{2}=\frac{39}{20}-\frac{15}{20}\)
\(x:\frac{1}{2}=\frac{24}{20}\)
\(x=\frac{24}{20}\times\frac{1}{2}\)
\(x=\frac{24}{40}\)
\(x=\frac{3}{5}\)
1: x=3/4-1/2=3/4-2/4=1/4
2: x-1/5=2/11
=>x=2/11+1/5=21/55
3: x-5/6=16/42-8/56
=>x-5/6=8/21-4/28=5/21
=>x=5/21+5/6=15/14
4: x/5=5/6-19/30
=>x/5=25/30-19/30=6/30=1/5
=>x=1
5: =>|x|=1/3+1/4=7/12
=>x=7/12 hoặc x=-7/12
6: x=-1/2+3/4
=>x=3/4-1/2=1/4
11: x-(-6/12)=9/48
=>x+1/2=3/16
=>x=3/16-1/2=-5/16
1)x= 1/4
2)x= 2/11+ 1/5
x= 21/55
3)x - 5/6 = 5/21
x = 5/21+5/6
x = 15/14
4)x/5 = 5/6 + -19/30
x:5 = 1/5
x = 1/5.5
x = 1
5) |x| - 1/4 = 6/18
|x| = 6/18 - 1/4
|x| =7/12
⇒x= 7/12 hoặc -7/12
6)x = -1/2 +3/4
x= 1/4
7) x/15 = 3/5 + -2/3
x:15 = -1/15
x = -1/15. 15
x = -1
8)11/8 + 13/6 = 85/x
85/24 = 85/x
⇒ x = 24
9) x - 7/8 = 13/12
x = 13/12 + 7/8
x = 47/24
10)x - -6/15 = 4/27
x = 4/27 + (-6/15)
x = -34/135
11) -(-6/12)+x = 9/48
x= 9/48 - 6/12
x = -5/16
12) x - 4/6 = 5/25 + -7/15
x -4/6 = -4/15
x = -4/15 + 4/6
x = 2/5
bài 1 : a,ta có 3/x-1 =4/y-2=5/z-3 => x-1/3=y-2/4=z-3/5
áp dụng .... => x-1+y-2+z-3 / 3+4+5 = x+y+z-1-2-3/3+4+5 = 12/12=1
do x-1/3 = 1 => x-1 = 3 => x= 4 ( tìm y,z tương tự
Bài 1:
a) Ta có: 3/x - 1 = 4/y - 2 = 5/z - 3 => x - 1/3 = y - 2/4 = z - 3/5 áp dụng ... =>x - 1 + y - 2 + z - 3/3 + 4 + 5 = x + y + z - 1 - 2 - 3/3 + 4 + 5 = 12/12 = 1 do x - 1/3 = 1 => x - 1 = 3 => x = 4 ( tìm y, z tương tự )
1: =>x/5=6/5
=>x=6
2: =>x^2=36
=>x=6 hoặc x=-6
3: =>x-5/2=3+1/6=19/6
=>x=19/6+5/2=19/6+15/6=34/6=17/3
4: =>x=1/2:2/5=1/2*5/2=5/4
a: \(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x+1+1}{x+1}+\dfrac{2}{y-2}=6\\\dfrac{5}{x+1}-\dfrac{1}{y-2}=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{x+1}+\dfrac{2}{y-2}=5\\\dfrac{5}{x+1}-\dfrac{1}{y-2}=3\end{matrix}\right.\)
=>x+1=1 và y-2=1/2
=>x=0 và y=5/2
b: \(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{4}{x-2y}=\dfrac{1}{2}-\dfrac{1}{18}=\dfrac{9}{18}-\dfrac{1}{18}=\dfrac{8}{18}=\dfrac{4}{9}\\\dfrac{2}{2x-y}=\dfrac{1}{18}+\dfrac{1}{x-2y}\end{matrix}\right.\)
=>x-2y=9 và 2/2x-y=1/18+1/9=1/18+2/18=3/18=1/6
=>x-2y=9 và 2x-y=12
=>x=5; y=-2
c: \(\Leftrightarrow\left\{{}\begin{matrix}10\left|x-6\right|+15\left|y+1\right|=25\\10\left|x-6\right|-8\left|y+1\right|=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}23\left|y+1\right|=23\\\left|x-6\right|=1\end{matrix}\right.\)
=>|x-6|=1 và |y+1|=1
=>\(\left\{{}\begin{matrix}x\in\left\{7;5\right\}\\y\in\left\{0;-2\right\}\end{matrix}\right.\)
a, x + \(\frac{1}{4}=\frac{5}{8}\)
x = \(\frac{5}{8}-\frac{1}{4}\)
x = \(\frac{5}{8}-\frac{2}{8}\)
x = \(\frac{3}{8}\)
b, x - \(\frac{1}{3}=\frac{1}{6}\)
x = \(\frac{1}{6}+\frac{1}{3}\)
x = \(\frac{1}{6}+\frac{2}{6}\)
x = \(\frac{3}{6}\)
x = \(\frac{1}{2}\)
c, \(Xx\frac{3}{5}=\frac{9}{10}\)
\(X=\frac{9}{10}:\frac{3}{5}\)
\(X=\frac{9}{10}x\frac{5}{3}\)
\(X=\frac{45}{30}\)
\(X=\frac{3}{2}\)
d, \(X:\frac{1}{6}=18\)
\(X=18x\frac{1}{6}\)
\(X=3\)
1) Do x ∈ Z và 0 < x < 3
⇒ x ∈ {1; 2}
2) Do x ∈ Z và 0 < x ≤ 3
⇒ x ∈ {1; 2; 3}
3) Do x ∈ Z và -1 < x ≤ 4
⇒ x ∈ {0; 1; 2; 3; 4}
1) (2 4/5+3 1/2).x =18/17
(14/5 + 7/2).x = 18/17
(28/10 + 35/10). x = 18/17
63/10.x = 18/17
x = 18/17 : 63/10
x =...(cái này bạn tự tính nhé :v )
2) Làm tương tự như phần 1
\(6\frac{1}{3}x-5\frac{1}{3}x=\frac{1}{7}\)
\(\Leftrightarrow\frac{19}{3}x-\frac{16}{3}x=\frac{1}{7}\)
\(\Leftrightarrow\frac{3}{3}x=\frac{1}{7}\)
\(\Leftrightarrow x=\frac{1}{7}\)
Vậy \(x=\frac{1}{7}\)
\(x+x\times\frac{1}{3}+\frac{5}{18}=1\frac{1}{6}\)
\(x+x\times\frac{1}{3}+\frac{5}{18}=\frac{7}{6}\)
\(x+x\times\frac{1}{3}=\frac{7}{6}-\frac{5}{18}\)
\(x+x\times\frac{1}{3}=\frac{8}{9}\)
\(x\times1+x\times\frac{1}{3}=\frac{8}{9}\)
\(x\times\left(1+\frac{1}{3}\right)=\frac{8}{9}\)
\(x\times\frac{4}{3}=\frac{8}{9}\)
\(x=\frac{8}{9}:\frac{4}{3}\)
\(x=\frac{2}{3}\)
Vậy \(x=\frac{2}{3}\)
#Y/n
\(x+x\times\frac{1}{3}+\frac{5}{18}=1\frac{1}{6}\)
\(x+x\times\frac{1}{3}+\frac{5}{18}=\frac{7}{6}\)
\(x+x\times\frac{1}{3}=\frac{7}{6}-\frac{5}{18}\)
\(x+x\times\frac{1}{3}=\frac{21}{18}-\frac{5}{18}\)
\(x\left(1+\frac{1}{3}\right)=\frac{16}{18}\)
\(x\left(\frac{3}{3}+\frac{1}{3}\right)=\frac{8}{9}\)
\(\frac{4}{3}x=\frac{8}{9}\)
\(x=\frac{8}{9}\times\frac{3}{4}\)
\(x=\frac{2}{3}\)