96/x-3=5 Tìm x
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\(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-3}{97}+\frac{x-4}{96}+\frac{x-5}{95}=5\)
\(\Rightarrow\left(\frac{x-1}{99}-1\right)+\left(\frac{x-2}{98}-1\right)+\left(\frac{x-3}{97}-1\right)+\left(\frac{x-4}{96}-1\right)+\left(\frac{x-5}{95}-1\right)\)\(=5-1-1-1-1-1\)
\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{98}+\frac{x-100}{97}+\frac{x-100}{96}+\frac{x-100}{95}=0\)
\(\Rightarrow\left(x-100\right).\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}+\frac{1}{95}\right)=0\)
Mà \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}+\frac{1}{95}\ne0\)
\(\Rightarrow x-100=0\)
\(\Rightarrow x=100\)
Vậy x=100
Chúc bạn học tốt
`[ ( 2 xx x - 11 ) : 3 + 1 ] xx 5 = 20`
`( 2 xx x - 11 ) : 3 + 1=20:5`
`( 2 xx x - 11 ) : 3 + 1=4`
`( 2 xx x - 11 ) : 3 =4-1`
`( 2 xx x - 11 ) : 3 =3`
`2xx x -11=3xx3`
`2xx x -11=9`
`2xx x =9+11`
`2 xx x=20`
`x=20:2`
`x=10`
Vậy `x=10`
`b, x - 96 = ( 443 - x ) - 15`
`x-96=443-x-15`
` x+x=443-15+96`
`2x=524`
`x=524:2`
`x= 262`
Vậy `x=262`
\(#Nqoc\)
`a)`
\([ ( 2 \times x - 11 ) \div 3 + 1 ] \times 5 = 20\)
`(2 \times x - 11) \div 3 + 1 = 20 \div 5`
`(2 \times x - 11) \div 3 + 1 = 4`
`(2 \times x - 11) \div 3 = 4 - 1`
`(2 \times x - 11) \div 3 = 3`
`2 \times x - 11 = 3 \times 3`
`2 \times x - 11 = 9`
`2 \times x = 9 + 11`
`2 \times x = 20`
`x = 20 \div 2`
`x = 10`
Vậy, `x = 10`
`b)`
\(x - 96 = ( 443 - x ) - 15\)
`x - 96 = 443 - x - 15`
`x - 96 = 428 - x`
`x = 428 - x + 96`
`x = 524 - x`
`x - 524 + x = 0`
`(x + x) - 524 = 0`
`2x - 524 = 0`
`2x = 524`
`x = 524 \div 2`
`x = 262`
Vậy, `x = 262.`
a) nếu tích = 0 => một trong hai số hạng = 0
nếu x-5=0 => x=5
nếu x-7=0 => x= 7
=> x thuộc {5;7}
b)96-3(x+1)=42
3.(x+1)=96-42=54
x+1=54:3=18
x=18-1=17
các bạn cho mk vài li-ke cho tròn 950 với
(x-5).(x-7)=0
=>x-5=0 =>x=5
hoac x-7=0=>x=7
96-3.(x+1)=42
3.(x+1) =96-42=54
(x+1) =54/3=18
x =18-1
x=7
\(96-3\left(x+1\right)=0\)
\(96-3x-3=0\)
\(93-3x=0\)
\(3x=93\)
\(x=31\)
vậy \(x=31\)
a, 5(x – 7) = 0
x – 7 = 0
x = 7
b, 95 – 5(x+2) = 45
5(x+2) = 40
x+2 = 8
x = 6
c, 6 2 x + 2 3 + 40 = 100
6(2x+8) = 60
2x+8 = 10
x = 1
d, 3(3x+9)+6 = 96
3(3x+9) = 90
3x+9 = 30
3x = 27
x = 9
e, 2 6 + 5 + x = 3 4
5+x = 81–64
5+x = 17
x = 12
\(\frac{x-2}{99}+\frac{x-3}{98}=\frac{x-4}{97}+\frac{x-5}{96}\Leftrightarrow\frac{x-2}{99}-1+\frac{x-3}{98}-1=\frac{x-4}{97}-1+\frac{x-5}{96}-1\)
<=>\(\frac{x-101}{99}+\frac{x-101}{98}=\frac{x-101}{97}+\frac{x-101}{96}\)
<=>\(\left(x-101\right)\left(\frac{1}{99}+\frac{1}{98}-\frac{1}{97}-\frac{1}{96}\right)=0\)
<=>x-101=0 \(\left(\frac{1}{99}+\frac{1}{98}-\frac{1}{97}-\frac{1}{96}\ne0\right)\)
<=>x=101