Thực hiện phép tính x 2 - 2 x ( x - 1 ) 2 + 2 - x x ( x - 1 ) 2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)
\(\dfrac{x}{x-2}+\dfrac{2}{2-x}\\ =\dfrac{x}{x-2}-\dfrac{2}{x-2}\\ =\dfrac{x-2}{x-2}\\ =1\)
b)
\(\dfrac{x^2}{x^2}-1\\ =1-1\\ =0??\)
\(=\left(\dfrac{1}{x\left(x+1\right)}+\dfrac{x-2}{x+1}\right):\left(\dfrac{1}{x}+x-2\right)\)
\(=\dfrac{x^2-2x+1}{x\left(x+1\right)}:\dfrac{x^2-2x+1}{x}\)
\(=\dfrac{1}{x+1}\)
Đặt \(x^2+1=a\)
Ta có: \(\dfrac{1}{x^2-x+1}-\dfrac{x^2+2}{x^2+1}+1\)
\(=\dfrac{1}{a-x}+\dfrac{a+1}{a}+1\)
\(=\dfrac{a}{a\left(a-x\right)}+\dfrac{\left(a+1\right)\left(a-x\right)}{a\left(a-x\right)}+\dfrac{a\left(a-x\right)}{a\left(a-x\right)}\)
\(=\dfrac{a+a^2-ax+a-x+a^2-ax}{a\left(a-x\right)}\)
\(=\dfrac{2a^2+2a-2ax-x}{a\left(a-x\right)}\)
\(=\dfrac{2\left(x^2+1\right)^2+2\left(x^2+1\right)-2x\left(x^2+1\right)-x}{\left(x^2+1\right)\left(x^2+1-x\right)}\)
\(=\dfrac{2\left(x^4+2x^2+1\right)+2x^2+2-2x^3-2x-x}{\left(x^2+1\right)\left(x^2-x+1\right)}\)
\(=\dfrac{2x^4+4x^2+2+2x^2+2-2x^3-3x}{\left(x^2+1\right)\left(x^2-x+1\right)}\)
\(=\dfrac{2x^4-2x^3+6x^2-3x+4}{\left(x^2+1\right)\left(x^2-x+1\right)}\)
Bài 2:
1: \(A=\left(x+2\right)\left(x^2-2x+4\right)+2\left(x+1\right)\left(1-x\right)\)
\(=\left(x+2\right)\left(x^2-x\cdot2+2^2\right)-2\left(x+1\right)\left(x-1\right)\)
\(=x^3+2^3-2\left(x^2-1\right)\)
\(=x^3+8-2x^2+2=x^3-2x^2+10\)
\(B=\left(2x-y\right)^2-2\left(4x^2-y^2\right)+\left(2x+y\right)^2+4\left(y+2\right)\)
\(=\left(2x-y\right)^2-2\cdot\left(2x-y\right)\left(2x+y\right)+\left(2x+y\right)^2+4\left(y+2\right)\)
\(=\left(2x-y-2x-y\right)^2+4\left(y+2\right)\)
\(=\left(-2y\right)^2+4\left(y+2\right)\)
\(=4y^2+4y+8\)
2: Khi x=2 thì \(A=2^3-2\cdot2^2+10=8-8+10=10\)
3: \(B=4y^2+4y+8\)
\(=4y^2+4y+1+7\)
\(=\left(2y+1\right)^2+7>=7>0\forall y\)
=>B luôn dương với mọi y
Bài 1:
5: \(x^2\left(x-y+1\right)+\left(x^2-1\right)\left(x+y\right)\)
\(=x^3-x^2y+x^2+x^3+x^2y-x-y\)
\(=2x^3-x+x^2-y\)
6: \(\left(3x-5\right)\left(2x+11\right)-6\left(x+7\right)^2\)
\(=6x^2+33x-10x-55-6\left(x^2+14x+49\right)\)
\(=6x^2+23x-55-6x^2-84x-294\)
=-61x-349
\(\left(1-x\right)\left(1+x\right)\left(1+x^2\right)\left(1+x^4\right)...\left(1+x^{20}\right)\)
\(=\left(1-x^2\right)\left(1+x^2\right)...\left(1+x^{20}\right)\)
\(=\left(1-x^{20}\right)\left(1+x^{20}\right)=1-x^{40}\)
\(\frac{x^2}{x^2+2x+1}\)\(-\)\(\frac{1}{x^2+2x+1}\)\(+\)\(\frac{2}{x +1}\)
= \(\frac{x^2-1+2\left(x+1\right)}{\left(x+1\right)^2}\)= \(\frac{x^2+2x+1}{x^2+2x+1}\)= 1